You would solve this by determining how many numbers from 1-10 can be multiples of 5. That's obviously 5 and 10. So that's 2/10 or reduced to 1/5. Now the second question you have to find how many numbers from 1-10 are prime. Prime is a number that can only be divided by 1 and itself. So that would leave you with 1, 3, 5, 7. I think where the trick comes into play is if you drew a 5 or 10 the first time, then you didn't place those cards back in the box, you couldn't draw them again. So the answer would 4/10 or 2/5 if you could draw the 5 again. Or I supposed if you had drew the 10 the first time and not the 5. I assume however, they want you to exclude 5 and 10 because it was part of the first section of this equation. So that would mean only 1, 3, and 7 or 3/10.
I think it is D since a universal set would only be {1,2,3,4,5,6,...} and the subset would not satisfy any of the conditions of symmetric, transitive, and reflexive.
