Umm. Where is the question?
For a given distribution of data, the sum of the relative frequencies is 1.
Thus, the completed table of relative frequencies is gives as:
Outcome 1 2 3 4 5
Rel. Freq. 0.1 0.1 0.3 0.1 0.4
Part a:
P({2, 3, 4}) = 0.1 + 0.3 + 0.1 = 0.5
Part b:
P(E') where E = {3, 4}
= 1 - P({3, 4}) = 1 - (0.3 + 0.1) = 1 - 0.4 = 0.6
A. 1.395
2.31 - 0.915 = 1.395