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3 years ago

-0.8662866239 is rational or irrational

Mathematics

2 answers:

Nataly [62]3 years ago

6 0

<span>irrational?
I honestly don't know i googled it and it's </span>
<span>irrational</span>

svet-max [94.6K]3 years ago

4 0

Answer:

<h2>Irrational.</h2>

Step-by-step explanation:

This number is irrational.

Decimal numbers can be finite or infinite. Specifically, irrational numbers are only infinite, but rational numbers can be both, infinite or finite. So, how to distinguish them?

Actually, we can see the difference looking for patterns or repetitions. When the decimal number is infinte but has a pattern like the number 1.6666666..., then that's a rational number, because its "rationality" is the pattern.

On the other hand, if the decimal number is infinite and it doesn't have a repetitive pattern, like the given -0.8662866239, then that's a irrational number, because it doesn't have a repetition which makes it "rational".

Therefore, the given number is irrational.

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3 years ago

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Answer:

We accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.

Step-by-step explanation:

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.

This means that the null hypothesis is:

$H_{0}: \mu = 50$

And the alternate hypothesis is:

$H_{a}: \mu \neq 50$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

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This means that $\mu = 50$

In a random sample of 36 bins, the sample mean amount was 50.67 pounds and the sample standard deviation was 3.9 pounds.

This means that $n = 36, X = 50.67, \sigma = 3.9$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{50.67 - 50}{\frac{3.9}{\sqrt{36}}}$

$z = 1.03$

p-value:

Since we are testing if the mean is differente from a value and the z-score is positive, the pvalue is 2 multipled by 1 subtracted by the pvalue of z = 1.03.

z = 1.03 has a pvalue of 0.8485

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2*0.1515 = 0.3030

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3 years ago