Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
1675/3890 you are dividing 1675 by 3890 so it equals 0.43059...=0.4 simplified to the first decimal
I think the answer is 5700
A box has 6 sides so you multiply 16.7 and 6 and you’ll get 100.2
ANSWER IS 100.2in
Excel expects a + or = sign before math calculations.
Also, for arguments of functions (such as sqrt), parentheses "()" are used. Brackets "[]" are not acceptable.
That leaves only one remaining option.