Answer:
7.0
Step-by-step explanation:
In ΔVWX, the measure of ∠X=90°, the measure of ∠W=9°, and WX = 8.7 feet. Find the length of XV to the nearest tenth of a foot.
I'm sorry but I couldn't really get that can u at least take a picture or something
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Answer:
125 meters
Step-by-step explanation:
Let distance = d and time is t
Using the variation;
d = k t^2
So let’s us get k
80 = k * 4*2
16k = 80
k = 80/16 = 5
So for 5 seconds, the distance would be;
d = 5 * 5^2
d = 125 meters