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3 years ago

A cars ............................

Mathematics

1 answer:

Nina [5.8K]3 years ago

4 0

C. 181.7 miles I believe

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Please help me factorize this x(a- <img src="https://tex.z-dn.net/?f=x%28a%20-b%29%20%2B%20a%20-%20b" id="TexFormula1" tit

Nostrana [21]

I’m not sure but I think it’s:
(a-b)(x+1)

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3 years ago

PLS HELP ME WITH GEOMETRY PLS :)

MArishka [77]

Answer:

-4, -24

Step-by-step explanation:

The location of Z is either +10 or -10 units away from Y, since YZ = 10. Then Z could be located at either -4 or -24.

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4 years ago

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What is 948 divided by 1,000

lana [24]

948 divided by 1,000 is 0.948

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4 years ago

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Eva8 [605]

Answer:

164 Cm^3

Step-by-step explanation:

Solution

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6 0

3 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago