Find the approximate height of the flagpole.
2 answers:
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Answer:
Step-by-step explanation:
The attached diagram shows the given triangle labelled as triangle ABC. Line DE is parallel to line AB. It means that triangle DEC is similar to triangle ABC. Comparing the sides,
DC/DE = AC/AB
DC = 5
DE = 8
AC = 5 + x
AB = 10
Therefore,
5/8 = (5+x)/10
Cross multiplying
5 × 10 = 8(5 + x)
50 = 40 + 8x
8x = 50-40 = 10
x = 10/8 = 1.25
Similarly,
CE/DE = CB/AB
CE = 7
CB = 7 + y
DE = 8
AB = 10
Therefore
7/8 = (7+y)/10
Cross multiplying
7 × 10 = 8(7 + y)
70 = 56 + 8y
8y = 70 - 56 = 14
y = 14/8 = 1.75
If the line is tangent to circle at point A and the radius ( suppose AO) has a slope of 2.5 then a slope of the tangent line is :
Explanation: The product of slopes of two perpendicular lines is -1. To get second slope we have to divide -1 by the first one.
Answer:C) - 0.4
Explanation: The product of slopes of two perpendicular lines is -1. To get second slope we have to divide -1 by the first one.
Answer:C) - 0.4