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Wittaler [7]
3 years ago
7

Gabriela Mistral was a poet, diplomat, teacher and humanitarian. Each week she worked a certain amount of days as a poet diploma

t teacher and humanitarian. This ratio was one day as a poet to one day as a diplomat to three days as a teacher to two days as a humanitarian how many days must she work as a humanitarian if she works 12 days as a teacher?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

Gabriela Mistral works as a humanitarian for 8 days.

Step-by-step explanation:

Gabriela Mistral was a poet, diplomat, teacher and humanitarian such that each week she worked a certain amount of days as a poet diplomat teacher and humanitarian.

Ratio is 1:1:3:2

Let x denotes total number of days Gabriela Mistral work.

As she works 12 days as a teacher,

\frac{3}{7}x=12\\ x=\frac{7}{3}(12)\\ x=28

Total number of days =x=28

So,

she works as a humanitarian for \frac{2}{7}x=\frac{2}{7}(28)=8 days.

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marta [7]
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lets start of with a regular cos(x) graph.  This starts on its maximum instead of minimum so we have to multiply it by -1 to get -cos(x) which does start on its minimum.

-cos(x) has an amplitude of 1 instead of 10, to fix that we multiply it by 10 to get -10cos(x) which has an amplitude of 10.
 
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-10cos((π/5)x) has a minimum of -10 and maximum of 10 instead of a minimum of -2 and maximum of 18, to fix this we add 8 to -10cos((π/5)x) to get -10cos((π/5)x)+8 which does have a minimum of -2 and maximum of 18.

Therefore the answer is y=-10cos((π/5)x)+8. x being time in minutes and and y being the height in feet.  

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8 0
3 years ago
What are the four points of intersection between 4x^2 + y^2 - 4y - 32 = 0 and x^2 - y - 7 = 0 ? Solve algebraically
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Remember (a²-b²)=(a-b)(a+b)

solve for  a single variable
solve for y in 2nd

add y to both sides
x²-7=y
sub (x²-7) for y in other equaiton

4x²+(x²-7)²-4(x²-7)-32=0
expand
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x⁴-14x²+45=0
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set each to zero

x-3=0
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x+3=0
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x+√5=0
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for x=-3
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for √5
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for -√5
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the intersection points are

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