3 years ago

Find the domain of the function

1 answer:

8 0

Domain are those values of x for which function is defined. f(x) is not defined at x = 3. Therefore Domain is

x∈ (⁻∞, +∞) - {3}

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Range of the function f(x) = -x^2 - 5

Naddik [55]

Answer:

Step-by-step explanation:

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3 years ago

Write the formula for the parabola that has x- intercepts (3,0) and (8,0), and y- intercept (0,−2)

alexira [117]

Answer: $x^2-5x=-12(y+2)$

Step-by-step explanation:

Given

Parabola has x-intercept has $(3,0)$ and $(8,0)$

and Y-intercept as $(0,-2)$

Now the general equation of parabola is

$y=ax^2+bx+c\quad \ldots(i)$

Substitute $(0,-2)$ in $(i)$ we get

$-2=c$

Now substitute $(3,0)$ in equation $(i)$

$0=a(3)^2+3b-2\quad \ldots(ii)$

Now substitute $(8,0)$ in equation $(i)$

$0=a(8)^2+8b-2\quad \ldots(iii)$

Solving $(ii)$ and $(iii)$ we get

$a=\frac{-1}{12}\ \text{and}\ b=\frac{5}{12}$

therefore

$y=\frac{-x^2}{12}+\frac{5x}{12}-2$

$12y=-x^2+5x-24$

5 0

3 years ago

What is <br><br> 6/1 divided by 3/4<br><br> if i put it in the wrong way.. then SORRY

Pani-rosa [81]

The answer is 8

Step by step:

6x4/1x3 =

24/3

(24/3)/(3/3) = 8

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3 years ago

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Which percent is equivalent to 0.03?

klasskru [66]

The correct answer would be C) 3%

6 0

3 years ago

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Let f(x)=cos(arctanx). What is the range of f?

Alenkasestr [34]

-π/2 < arctan(x) < π/2

So cos(π/2) < cos(arctan(x)) < cos(0)

0 < cos(arctan(x)) < 1

4 0

3 years ago