Answer:
y=1
x=2/5
Step-by-step explanation:
1=-5x+3
-2=-5x
x=2/5
Answer:
197 in ^2 (answer B of the list)
Step-by-step explanation:
Notice that this figure has a total of 6 faces, four of which are rectangles (whose area is calculated as "base times height") and two trapezoids (whose area is (B+b)H/2 ).
The total surface area is therefore the addition of these six areas:
Rectangles:
5 in x 5 in = 25 in^2
5 in x 5 in = 25 in^2
5 in x 6.4 in = 32 in^2
9 in x 5 in = 45 in^2
Trapezoids:
Two of equal dimensions: B = 9 in, b = 5 in, H = 5 in
2 * (9 in + 5 in) 5 in /2 = 70 in^2
Which gives a total of (25 + 25 + 32+45 + 70) in^2 = 197 in^2
This agrees with answer B of he provided list.
StartFraction 3 pi Over 4 EndFraction radians
Step-by-step explanation:
Pi radians is equal to 180°
Given the minor arc angles as 135°, change this value to pi radians
180° =π radians
135° = ?
Cross multiply
135° * π radians / 180°
=135/180 * π radians
=3 π/4 radians
Learn More
Changing degrees to radians :brainly.com/question/12095161
Keywords: minor arc, measure, circle, line segment, radii, central angle
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Answer:
6
Step 1: Solve Square Root
Vx+3=x-3
x+3=(x-3)^2 (squared both sides)
x+3=x^2-6x+9
x+3-(x^2-6x+9)=0
(-x+1)(x-6)=0 (factor left side of equation)
-x+1=0 or x-6=0
x=1 or x=6
When you plug it in to check
1 (Doesn't Work)
6 (Work)
Therefore, 6 is your solution.
Answer:
- zeros: x = -3, -1, +2.
- end behavior: as x approaches -∞, f(x) approaches -∞.
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).