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castortr0y [4]
2 years ago
12

Heeeeeeeeeeeeeeeeelp

Mathematics
1 answer:
mel-nik [20]2 years ago
8 0

Answer:6hrs and &270

8hours and &360

9.5hours and&427.50

Step-by-step explanation:

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(Please help!!)<br> Find -5A + 4B
Natalija [7]

Answer:

I think it 7 ok ok ok ok ok ok

7 0
2 years ago
PLS HELP ME ASAP WITH QUESTION 30! THANK YOU SO MUCH!!!
nika2105 [10]
30. is just asking where the two equations graphed intersect each other...

x = -3 and x = 1 for intersections.
8 0
3 years ago
You are comparing cell phones. The old model is 7/8 of an inch thick. The new model is 3/5 of an inch thick. How much thinner is
Sloan [31]

The new model is 11/40 of an inch thinner than the old model.

In order to do this, we need to subtract the new model from the old model.

7/8 - 3/5

In order to complete this, we will need common denominators.

35/40 - 24/40

Then simply complete the operation.

11/40

3 0
3 years ago
PLEASE HELP.
notka56 [123]

Answer:

(3, -3)

Step-by-step explanation:

To solve for a system of equations, use substitution.

First, solve for one variable in an equation.

2x - 3y = 15

Add 3y to both sides.

2x = 3y + 15

Divide both sides by 2 to get x by itself.

x = 1.5y + 7.5

Put this in the other equation.

5x + 2y = 9

Substitute the variable.

5(1.5y + 7.5) + 2y = 9

Distribute the 5 inside the 1.5y + 7.5.

7.5y + 37.5 + 2y = 9

Combine like terms.

9.5y + 37.5 = 9

Subtract 37.5 from both sides.

9.5y = -28.5

Divide both sides by 9.5.

y = -3.

Now take this value and put it in the other equation to get your x.

2x - 3y = 15

Substitute variable.

2x - 3(-3) = 15

Multiply.

2x + 9 = 15

Subtract 9 from both sides.

2x = 6

Divide both sides by 2.

x = 3.

Your pair is (3, -3).

4 0
2 years ago
There are 10 kids on the math team. Two kids will be selected from the team to compete in the state competition. How many ways a
patriot [66]

Answer:

45 ways

Step-by-step explanation:

Total number of kids = 10

We have to select the 2 kids

So the number ways to select two kids ^{10}C_2

We know that ^{n}C_r=\frac{n!}{r!(n-r)!}

So ^{10}C_2=\frac{10!}{2!(10-2)!}=\frac{10!}{2!\times 8!}=\frac{10\times 9\times 8!}{2\times 8!}=45

So there are 45 ways to select 2 competitors

8 0
3 years ago
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