Answer:
X<12
Step-by-step explanation:
x² - x - 12 <0 any number without a power is to power 1.
x² - x^1 - 12<0
x^1 - 12 <0
x - 12 <0 any to the power 1 is that same number example p^1=p
x - 12 + 12<0 + 12
x<12
Answer:
Step-by-step explanation:
Since the bases are different, each expression must be done independently.
6.7*10^8
6.7*6.7*6.7*6.7*6.7*6.7*6.7*6.7= 4,060,676.78
1.2*10^2
1.2*1.2= 1.44
multiply the two= 5847374.56
Answer:
Again its C like i answered before.
Step-by-step explanation:
Cos is adj/hyp and there is only one cos option so it must be correct.
The complete question in the attached figure
we know that
The
interquartile range is a measure of where the “middle fifty<span>” is in a data set
</span>
the interquartile range formula is the first quartile subtracted from the third quartile:
IQR = Q3 – Q<span>1
</span><span>Group A [1 2 1 1 3 5 4 2 3]
</span>Step 1:
Put the numbers in order
<span>[1 1 1 2 2 3 3 4 5]
</span>Step 2:
Find the <span>median
</span>[1 1 1 2
2 3 3 4 5]
Step 3:
Place parentheses around the numbers above and below the median
[(1 1 1 2)
2 (3 3 4 5)]
Step 4:
Find Q1 and Q3
[(1 1 1 2)
2 (3 3 4 5)]----> Q1=1 Q3=3
IQRA = Q3 – Q1--------> 3-1=2
Group B [3 2 3 2 2 2 1 1 2]
Step 1:
Put the numbers in order
[1 1 2 2 2 2 2 3 3]
Step 2:
Find the median
[1 1 2 2
2 2 2 3 3]
Step 3:
Place parentheses around the numbers above and below the median
[(1 1 2 2)
2 (2 2 3 3)]
Step 4:
Find Q1 and Q3
[(1 1 2 2)
2 (2 2 3 3)]----> Q1=1 Q3=2
IQRB = Q3 – Q1--------> 2-1=1
IQRA=2
IQRB=1
the answer is the option
The interquartile range for Group A students is 1 more than the interquartile range for Group B students