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xxMikexx [17]
3 years ago
13

PLZ HURRY, 20 POINTS. Is this equation true or false, if its true tell the answer, if its false than no answer.

Mathematics
2 answers:
Kryger [21]3 years ago
5 0

THIS is true because

4x=2x +2x +5(x-x) 

4x= 4x + 5x-5x/ neq

4x=4x

N76 [4]3 years ago
5 0
4x = 2x + 2x
and +5(x - x) = 5(0) or 5×0 = 0
so it's true!
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Solve the inequality x^2 - x - 12 <0
pychu [463]

Answer:

X<12

Step-by-step explanation:

x² - x - 12 <0 any number without a power is to power 1.

x² - x^1 - 12<0

x^1 - 12 <0

x - 12 <0 any to the power 1 is that same number example p^1=p

x - 12 + 12<0 + 12

x<12

8 0
3 years ago
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(6.7x10 with an exponent of 8)(1.2x10 with an exponent of 2) please help!
finlep [7]

Answer:

Step-by-step explanation:

Since the bases are different, each expression must be done independently.

6.7*10^8

6.7*6.7*6.7*6.7*6.7*6.7*6.7*6.7=  4,060,676.78

1.2*10^2

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4 0
3 years ago
Small earthworms travel at speeds of about 0.2 centimeters per second. What is this speed in meters per second
Westkost [7]
0.002 meters per second
6 0
3 years ago
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Question 5 (25 points)
DiKsa [7]

Answer:

Again its C like i answered before.

Step-by-step explanation:

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7 0
3 years ago
wo groups of students were asked how many pets they had. The table below shows the numbers for each group: Group A 1 2 1 1 3 5 4
Elodia [21]
The complete question in the attached figure

we know that
The interquartile range is a measure of where the “middle fifty<span>” is in a data set
</span>

the interquartile range formula is the first quartile subtracted from the third quartile:

IQR = Q3 – Q<span>1

</span>
<span>Group A [1 2 1 1 3 5 4 2 3]
</span>Step 1: Put the numbers in order
<span>[1 1 1 2 2 3 3 4 5]
</span>Step 2: Find the <span>median
</span>
[1 1 1 2 2 3 3 4 5]
Step 3: Place parentheses around the numbers above and below the median
[(1 1 1  2) 2 (3 3 4 5)]
Step 4: Find Q1 and Q3
[(1 1 1  2) 2 (3 3 4 5)]----> Q1=1          Q3=3
IQRA = Q3 – Q1--------> 3-1=2

Group B [3 2 3 2 2 2 1 1 2]
Step 1: Put the numbers in order
[1 1 2 2 2 2 2 3 3]
Step 2: Find the median
[1 1 2 2 2 2 2 3 3]
Step 3: Place parentheses around the numbers above and below the median
[(1 1 2  2) 2 (2 2 3 3)]
Step 4: Find Q1 and Q3
[(1 1 2  2) 2 (2 2 3 3)]----> Q1=1         Q3=2
IQRB = Q3 – Q1--------> 2-1=1

IQRA=2
IQRB=1

the answer is the option 
The interquartile range for Group A students is 1 more than the interquartile range for Group B students

6 0
3 years ago
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