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4 years ago

I need to find the missing variables on the triangles but I don't know how

Mathematics

1 answer:

elixir [45]4 years ago

4 0

You would add 12+15 then subtract it from 32 to get your missing varible

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One month Mr. Moore made 3 withdrawals of $20 and 1 withdrawal for $80 from his account. How did the withdrawals change the amou

Flura [38]

Answer:

It decreased the amount of money in his bank account by $100

Step-by-step explanation:

When you withdraw money you you are taking money away so you are decreasing the amount of money in Mr. Moore's bank account by $100 dollars.

5 0

3 years ago

Please answer correctly ASAP !!!!!! Will mark brainliest !!!!!!!!!

BigorU [14]

Answer:

X=3/2 and 2/3

Step-by-step explanation:

6x^2 - 13^x + 6= 0

6x^2 - 4x - 9x + 6=0

By factorising...

2x(3x - 2) - 3(3x - 2)=0

(2x - 3) (3x - 2)=0

2x - 3=0

2x=3

X=3/2

3x - 2=0

3x=2

X=2/3

Hence, X=3/2 and 2/3

7 0

3 years ago

Find the values of the unknown angles marked with letters. 50 points!!!!!!!

IceJOKER [234]

Answer:

a = 115°, alternate interior angles are congruent
b = 70°, same as above
c = 180° - 115° = 65°, angles forming a straight angle are supplementary
d = 180° - 70° = 110°, same as above

3 0

3 years ago

Read 2 more answers

At time t=0, water begins to drip out of a pipe into an empty bucket. After 48 minutes, there are 12 inches of water in the bu

morpeh [17]

Answer:

W = (1/7) t

Step-by-step explanation:

At t = 0, W = 0

At t = 56 minutes , W = 8 inches

W = k*t The y intercept = 0 because t = 0 W = 0

8 inches = k * 56 minutes

k = 8 / 56

k = 1/7 inches / minute

W = (1/7) t

5 0

3 years ago

Write an exponential function y = abx for a graph that includes (–3, 16) and (–1, 4) f(x) = 2(0.5)x f(x) = 0.5(2)x f(x) = 4(0.3)

Arisa [49]

Answer: $f(x)=2(0.5)^x$

Step-by-step explanation:

Given, the exponential function $y = ab^x$ for a graph that includes (–3, 16) and (–1, 4).

On putting these points, we will have

$f(-3)=16=ab^{-3}\\\\ f(-1)=4=ab^{-1}$

Now,

$\dfrac{f(-3)}{f(-1)}=\dfrac{16}{4}=\dfrac{ab^{-3}}{ab^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b^{-3}}{b^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b}{b^3}=\dfrac{1}{b^2}\\\\\Rightarrow\ b^2=\dfrac{1}{4}\\\\\Rightarrow\ b=\pm\dfrac{1}{2}=\pm0.5$

since the multiplicative factor cannot be negative, so b= 0.5.

At b= 0.5

$4=a(0.5)^{-1}\\\\\Rightarrow\ 4=a(\dfrac{1}{2})^{-1}\\\\\Rightarrow\ 4=a(2)\\\\\Rightarrow \ a=2$

So, the required function is $f(x)=2(0.5)^x$ .

3 0

4 years ago