The formula for the area of a trapezium is as follows:
<span>area=<span>12</span>(a+b)h
</span>
Let a be the shorter base. Then a = h + 3.
Let b be the longer base. Then b = h + 7.
Substituting these values for a and b in the general formula gives:
<span>
area = 225 = <span>12</span>(h+3+h+7)h = <span>h^2</span>+5h</span>
So you need to solve the following quadratic:
<span><span>h^2</span>+5h−225=0</span>
Step 1: Use quadratic formula with a=1, b=5, c=-225.
<span>h=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>h=<span><span><span>−<span>(5)</span></span>±<span>√<span><span><span>(5)</span>2</span>−<span><span>4<span>(1)</span></span><span>(<span>−225</span>)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>h=<span><span><span>−5</span>±<span>√925</span></span>2</span></span><span><span>h=<span><span><span>−5/</span>2</span>+<span><span><span><span>5/2</span><span>√37</span></span><span> or </span></span>h</span></span></span>=<span><span><span>−5/</span>2</span>+<span><span><span>−5/</span>2</span><span>√37
</span></span></span></span>Answer:<span><span>h=<span><span><span>−5/</span>2</span>+<span><span><span><span>52</span><span>√37</span></span><span> or </span></span>h</span></span></span>=<span><span><span>−5/</span>2</span>+<span><span><span>−5/</span>2</span><span>√<span>37</span></span></span></span></span>
Answer:
<em>x = 62°, y = 103°</em>
Step-by-step explanation:
<u>Supplementary Angles</u>
Two angles are called <em>supplementary</em> when their measures add up to 180 degrees.
The image shows two pairs of supplementary angles. We have to find the value of the unknown variable.
The first drawing shows supplementary angles x and 118°. They must satisfy the equation:
x + 118° = 180°
Subtracting 118°:
x = 180° - 118°
x = 62°
From the second drawing, we set up the equation:
y + 77° = 180°
Subtracting 77°:
y = 180° - 77°
y = 103°
The difference quotient of the function that has been presented to us will turn out to be 5.
<h3>How can I calculate the quotient of differences?</h3>
In this step, we wish to determine the difference quotient for the function that was supplied.
To begin, keep in mind that the difference quotient may be calculated by:
Lim h->0 
Now, for the purpose of the function, we need this:
Then we will have:
j(x) = 5x - 3
Then the following will be true:
Therefore, 5 is the value of the difference quotient for j(x) is %
Read the following if you are interested in finding out more about difference quotients:
brainly.com/question/15166834
#SPJ1
Answer:
Given the function f(x) = 3x + 1, evaluation of f(a + 1) gives:
C. 3a + 4
Step-by-step explanation:
Given function:
f(x) = 3x + 1
We have to find f(a+1).
For this purpose, we will take x = a+1 and
substitute it in the function f(x) = 3x+1:
f(x) = 3x + 1
f(a+1) = 3(a+1) +1
f(a+1) = 3(a) + 3(1) +1
f(a+1) = 3a+3+1
f(a+1) = 3a + 4
So the function f(a+1) is equal to option C. 3a + 4.
Answer:
a = 28.14 (Estimated)
Step-by-step explanation:
7a + 50 = 247
=> 7a = 197
=> a = 28.1428571429 (Using Calculator)
=> a = 28.14 (Estimated)
Hoped this helped.
