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3 years ago

PLEASE HELP?!

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

The middle point of BC is (0,2), the midpoint of CD is (1,0)
to prove two lines are parallel, prove their slopes are the same.
slope of BD: m=rise/run=4/-2=-2 (the run is negative because to get to B from D on the grid, you have to move from right to left, then upward. If the horizontal move is from left to right, the run is positive)
slope of EG: m=rise/run=2/-1=-2
EG and BD have the same slope, so they are parallel.

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Given a 5 liter jar and a 3 liter jar and a unlimited supply of water, how do you measure out 4 liter exactly

andre [41]

Answer:

Given:

5 liter Jar

3 liter jar

Unlimited supply of water.

To measure out 4 liters exactly.

Steps to be carries out to measure out 4 liters of water exactly.

Water content: 3 liter jar = Empty , 5 liter jar = Empty

1) Fill the 3 liter jar completely with water.

3 liter jar = 3 liter , 5 liter jar = Empty

2) Empty the filled 3 liter jar of water by pouring it out into 5 liter jar.

Water content: 3 liter jar = Empty , 5 liter jar = 3 liter

3) Again fill the empty 3 liter jar completely.

Water content: 3 liter jar = 3 liter , 5 liter jar = 3 liter

4) Pour water from 3 liter jar into 5 liter jar until it is completely filled.

Water content: 3 liter jar = 1 liter , 5 liter jar = 5 liter

5) Empty the 5 liter jar completely.

Water content: 3 liter jar = 1 liter , 5 liter jar = Empty

6) Empty the 3 liter jar by pouring the water into 5 liter jar.

Water content: 3 liter jar = Empty , 5 liter jar = 1 liter

7) Fill the 3 liter jar completely with water.

Water content: 3 liter jar = 3 liter , 5 liter jar = 1 liter

8) Empty the 3 liter jar by pouring it into 5 liter jar.

Water content: 3 liter jar = Empty , 5 liter jar = 4 liter

Now, we have exactly 4 liters of water in the 5 liter jar.

7 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

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2 years ago

80% of what number is 64

Thepotemich [5.8K]

Make an equation.

80% = 0.8

'of' is multiplication

'what number' is 'x'

'is' is an equal sign

0.8 * x = 64

0.8x = 64

Divide 0.8 to both sides:

x = 80

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago