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shepuryov [24]
3 years ago
11

PLEASE HELP ME WITH THIS QUESTION!!!

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0
The answer is no solution
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3 years ago
(a) The area of a rectangular parking lot is 3657 m².
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4 0
2 years ago
Read 2 more answers
Question:
DanielleElmas [232]

Given A room is half as long again as it is broad

Let the breadth of the room x m

length of the room x + x/2 = 3x/2m

Area of the room , x × 3x/2 =<em> 3x²/2m</em>

Given , cost of carpeting the room at Rs. 3.25m⁻²

So , total cost , 3x²/2 × 3.25

But , Total cost of carpeting is given as 175.50 so ,

  • (3x²/2 )× 3.25 = 175.50
  • x² = 175.50 × 2 / 3.25 × 3
  • x² = 36
  • x = 6

  • Breadth x = 6 m
  • length 3x/2 = 9m

let the height of the room H m

Area of the four wall = 2(L+ b)× h 2(6+9)× H

= 30H m²

Area of the of the one door and two window is 8m²

8m² Area to be prepared = Area of four wall - area of two window and 1 door = (30H - 8) m²

Given cost of preparing wall is Rs. 1.40m²

total cost of preparing wall is (30H - 8) × 1.40

Total cost of preparing wall is given as 240.80

comparing , (30H - 8 ) × 1.40 = 240.80

  • (30H - 8 ) = 240.80 /1.40 = 172
  • 30H -. 8 = 172
  • 30H = 180
  • H = 180/30 = 6

Hence, Dimensions of the room are lengths 9m , breadth 6m and height 6m

3 0
2 years ago
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