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OLga [1]
3 years ago
15

What is

ormula"> given that x \geq 6
Mathematics
1 answer:
Fofino [41]3 years ago
7 0

9514 1404 393

Answer:

  x - 6

Step-by-step explanation:

For values of x greater than or equal to 6, the difference x-6 is non-negative, so the absolute value function does nothing. The value is ...

  x -6

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Select TWO expressions that
8090 [49]

Answer:

A and D

Step-by-step explanation:

4×3=12

4×d=4d

12+4d

Then;(4×d)+(3×4)=4d +12

Same expression

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2 years ago
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What’s 93/108 in simplest form
mafiozo [28]
31/36 is the correct answer
4 0
3 years ago
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3
Natali [406]

Answer:

468.75

Step-by-step explanation:

Multiply the sales by the commision as a decimal to get the commission, in this case, 1875 * 1/4 = 468.75.

8 0
3 years ago
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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
Somebody please help me help me on this it’s GEOMETRY it is URGENT please DO NOT waste my answers
Norma-Jean [14]

Answer:

∠G ≅ ∠Q

Step-by-step explanation:

<u>Given</u>

  • ΔBIG ≅ ΔPQZ

<u>Answer choices:</u>

  • BI≅PQ - yes correct, corresponding
  • ∠B ≅ ∠P - yes correct, corresponding
  • ∠G ≅ ∠Q - no, incorrect, it should read ∠G ≅ ∠Z
  • ZP ≅ GB -  yes correct, corresponding

So, incorrect choice is the third one

8 0
3 years ago
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