Math/Physics Problem (I'd be glad if you solved one of them).
1 answer:
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Answer:
And replacing 8 for the possible cases and 52 for the total number of cards for a single selection we got:
Step-by-step explanation:
For a standard deck we need to remember that we have 4 types suits of Spades, Hearts, Diamonds, and Clubs. And in total 13 possible options A,2,3,4,5,6,7,8,9,10,J,Q,K.
If we want the probability that a card selected would be greater than 2 and less than 5 means that we are interested in the cards with denomination 3's and 4's because the card can't be 2 or 5.
And from the previous info we know that we have four cards for the 4's and four for the 3's so then we have a total of 8 possible cards in the standard deck of 52 who satisfy the conditions required.
And then we can find the probability desired with this formula:
And replacing 8 for the possible cases and 52 for the total number of cards for a single selection we got: