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Varvara68 [4.7K]
3 years ago
12

The Healy family drove 192 miles in 4.5 hours. How many miles could they drive at this rate in 3 hours

Mathematics
1 answer:
Alja [10]3 years ago
4 0
Let’s find this out by using proportions! it is very easy to do

192 miles/4.5 hours = m/3 hours

192 * 3 = 4.5 * m cross multiply

576 = 4.5m

576 / 4.5 = m divide both sides by 4.5

128 = m

your answer is 128 miles! hope this helped, blessings! x

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Goryan [66]

Answer:

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5 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Solve: 3n - 6 = -8(6 +5n)<br> and explain how to solve it
hjlf

Answer:

Step-by-step explanation:

First use distributive property: a(b + c) = a*b + a*c

3n - 6 = -8(6 + 5n)

3n - 6 = 6 * (-8) + 5n *(-8)

3n - 6 = -48 - 40n

Now add 40n to both sides

3n - 6 + 40n = -48 - 40n + 40n

43n - 6 = -48

Now add 6 to both sides

43n - 6 + 6 = -48 + 6

           43n = -42

               n = -42 /43

4 0
3 years ago
Read 2 more answers
two trains leaves stations 320miles apart at the same time and travel toward eachother. One train travels at 110 miles per hour
I am Lyosha [343]

x/110 = (320-x)/90

<span> Cross multiply</span>

90x = 35200-110x

200x=35200

X = 35200/200 = 176 (distance traveled by train going 110 mph

176/110 = 1.6 hours = 1 hour and 36 minutes

 

Check: 110*1.6 = 176, 90*1.6 = 144

176+144 = 320

it will take 1.6 hours ( 1 hour 36 minutes) for the trains to meet
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3 years ago
What is the value of R?<br><br> 3r–8=7+8r
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The answer to r is going to be the lucky number 5
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