Answer: Choice D. y = (x-1)^2 - 3
The vertex is (h,k) = (1,-3). So h = 1 and k = -3.
We have a = 1 as the leading coefficient.
Plug those values into the equation below
y = a(x-h)^2 + k
y = 1(x - 1)^2 + (-3)
y = (x - 1)^2 - 3
Should be zero, I believe.
The formula for circumference of a circle
=
2
π
r
The radius
=
3
c
m
(assuming units to be in cm)
2
π
r
=
2
×
22
7
×
3
=
132
7
=
18.86
c
m
Answer:
(0,-1),(1,0),(2,1),(3,2)
Step-by-step explanation:
We are given that a relation
y=x+1y=x+1
We have to find the four points contained in the inverse
The given function is linear function
Therefore,
Domain of function=R
Range of function=R
x=y-1x=y−1
Now, replace x by y and y replace by x
y=x-1y=x−1
Now, substitute y=f^{-1}(x)=f
−1
(x)
f^{-1}(x)=x-1f
−1
(x)=x−1
It is linear function and defined for all real values.
Substitute x=0
f^{-1}(0)=-1f
−1
(0)=−1
Substitute x=1
f^{-1}(1)=1-1=0f
−1
(1)=1−1=0
f^{-1}(2)=2-1=1f
−1
(2)=2−1=1
f^{-1}(3)=3-1=2f
−1
(3)=3−1=2
Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)
