The statements that describe features of an ipv4 routing table on a router include:
- Directly connected interfaces will have two route source codes in the routing table.
- If a default static route is configured in the router, an entry will be included in the routing table with source code.
It should be noted that the IPv4 route table is important for listing entries that are in the routing table.
The routing table of every router is unique and can be stored in the read access memory (RAM) of the device.
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Answer:
Explanation:
The following is written in Java and prints out the pattern to and from the first num parameter that is passed to the function. Meaning it goes from num1 to 0 and then from 0 to num1 again. It prints all of the values in a single line seperated by a space and a test case was used using the values provided in the question. The output can be seen in the attached picture below.
static void printNumPattern(int n1,int n2){
System.out.print(n1 + " ");
if(n1<=0) {
return;
} else {
printNumPattern(n1-n2,n2);
}
System.out.print(n1 + " ");
}
B.................................
Answer:
If you want to use a js variable in a php script you MUST pass it within a HTTP request. There are basically two ways: Submitting or reloading the page.
Explanation:
In programming, just like in algebra, we use variables in expressions (total = price1 + price2). From the example above, you can calculate the total to be 11. JavaScript variables are containers for storing data values. All JavaScript variables must be identified with unique names. These unique names are called identifiers.
Answer:
213
Explanation:
The given parameters are;
The network on which the host is on = 192.168.146.0
The subnet mast = 255.255.255.0
The binary value of the host portion = 11010101
To convert the binary value to decimal value, we proceed by multiplying each of the digits of the binary value by the corresponding power of 2, from the left to right, starting from a power of 0, and sum the result, as follows;
(11010101)₂ = (1×2⁷ + 1×2⁶ + 0×2⁵ + 1×2⁴ + 0×2³ + 1×2² + 0×2¹ + 1×2⁰)₁₀
1×2⁷+1×2⁶+0×2⁵+1×2⁴+0×2³+1×2²+0×2¹+1×2⁰= 128+64+0+16+4+1 = 213
∴ (11010101)₂ = (213)₁₀
The decimal value of 11010101 is 213.
