Answer:
Step-by-step explanation:
EI = IG . . . . . . . . . . . .diagonals of a rectangle bisect each other
2x +7 = 6x -13 . . . . . substitute given expressions
20 = 4x . . . . . . . . . . add 13-2x
5 = x . . . . . . . . . .. . . divide by 4
EI = 2x+7 = 2·5 +7 = 17
FH = 2·EI = 2·17
FH = 34
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∠IGF = ∠IFG = ∠IEH = ∠IHE = 59° . . . . mirror symmetric angles are congruent
∠EIH = 180° -∠IEH -∠IHE = 180° -2(59°)
∠EIH = 62°
Answer:
62.83 cm is the length of the ribbon needed
Answer:
The smoothing constant alpha is 0.20 (Option a)
Step-by-step explanation:
To solve this problem, first we write the succession of the simple exponential smoothing:

Where s(t) is the forecast for period t, s(t-1) is the forecast for period (t-1), xt is the real demand for period t, and alpha is the smoothing constant.
All but the alpha constant are known
s(t)=109.2
s(t-2)=110
xt=110-4=106
Then, we can calculate alpha as:

I’m not exactly sure but maybe f(0) = 4 and g(–2) = 4
Answer:
x=7
Step-by-step explanation: