Answer:
Step-by-step explanation:
Slope of line through (-9,6) and (-6,-9) = (-9 - 6)/(-6 - (-9)) = (-15)/(3) = -5
point-slope equation for line of slope -5 that passes through (-9,6):
y-6 = -5(x+9)
In a regular octagon it is impossible to have an acute angle!
Hope this helps!!
The equation of the line is
x
2
−x
1
x−x
1
=
y
2
−y
1
y−y
1
Here (−3,4)≡(x
1
,y
1
),(4,5)≡(x
2
,y
2
)
∴
4+3
x+3
=
5−4
y−4
⇒
7
x+3
=
1
y−4
⇒x+3=7(y−4)
⇒x+3=7y−28
⇒x−7y+3+28=0
⇒x−7y+31=0
please follow me also
-5/2 is the answer to your question
1.25 is the slope 5/4 rise over run
