Answer:
designing the computer network
Explanation:
Answer:
domain name (2 words, 10 letters)
Answer:
The answer to this question is given below in the explanation section. the correct option is C.
Explanation:
This is Java code statement:
System.out.print("Computing\nisInfun");
The output of this code statement is
Computing
isInfun
However, it is noted that the C option is not written correctly, but it is guessed that it will match to option C.
This Java code statement first prints "Computing" and then on the next line it will print "isInfun" because after the word "Computing" there is a line terminator i.e. \n. when \n will appear, the compiler prints the remaining text in the statement on the next line.
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
<span>Satellite images are based on data obtained by landsat satellites. </span>
