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diamong [38]
3 years ago
6

In a C++ program, one and two are double variables and input values are 10.5 and 30.6. After the statement cin >> one >

> two; executes, ____.
Computers and Technology
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

variable one stores 10.5 and two stores 30.6

Explanation:

In c++ language, the cout keyword is used to write to the standard output. The input from the user is taken by using the cin keyword.

For the input from the user, a variable need is declared first.

datatype variable_name;

The input can be taken one at a time as shown.

cin >> variable_name;

The input for more than one variable can be taken in a single line as given by the syntax below.

1. First, two variables are declared.

datatype variable_name1, variable_name2;

2. Both input is taken simultaneously as shown.

cin >> variable_name1, variable_name2;

For the given scenario, two double variables are declared as below.

double one, two;

The question mentions input values for the two double variables as 10.5 and 30.6.

3. The given scenario takes both the values as input at the same time, in a single line as shown below.

cin >> one >> two;

4. After this statement, both the values entered by the user are accepted.

The values should be separated by space.

First value is stored in the variable one.

Second value is stored in the variable two.

5. The user enters the values as follows.

10.5 30.6

6. The value 10.5 is stored in variable one.

7. The value 30.6 is stored in variable two.

The c++ program to implement the above is given below.

#include <iostream>

using namespace std;

int main() {

   double one, two;      

   cout << " Enter two decimal values " << endl;

   cin >> one >> two;

   cout << " The input values are " << endl;

   cout << " one : " << one << " \t " << " two : " << two << endl;

   return 0;

}

OUTPUT

Enter two decimal values  

10.5 30.6

The input values are  

one : 10    two : 530.6

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Answer:

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3 years ago
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Anastasy [175]

Answer:

rtg

Explanation:

rth

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To solve the difficulty of scaling memory organization, memories are physically organized into a ____-dimensional organization.
Brums [2.3K]

Answer: two

Explanation:

Organizational memory is simply referred to as the accumulation of data or information that have been created for a particular organization.

To solve the difficulty of scaling memory organization, memories are physically organized into a two dimensional organization.

3 0
3 years ago
Create union floatingPoint with members float f, double d and long double x. Write a program that inputs values of type float, d
Kitty [74]

Answer:

Here the code is given as follows,

#include <stdio.h>

#include <stdlib.h>

union floatingPoint {

float floatNum;

double doubleNum;

long double longDoubleNum;

};

int main() {

union floatingPoint f;

printf("Enter data for type float: ");

scanf("%f", &f.floatNum);

printf("\nfloat %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type double: ");

scanf("%lf", &f.doubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type long double: ");

scanf("%Lf", &f.longDoubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

return 0;

}

5 0
3 years ago
(True/False). In an "ID" column with the data type INTEGER PRIMARY KEY, each value entered for the ID must be unique.
musickatia [10]

Answer:

The answer is "True".

Explanation:

  • The key to a relational database that is unique for each data record is a primary key, also called a primary keyword.
  • This unique identifier, including a driver's license name, telephone number, or vehicle identification number. This is an identifier (VIN).
  • There must always be the only primary key in such a relational database.
  • This is a specific relational database field (or column combination) that identifies each table entry in a unique way.
  • It utilized it to swiftly analyze the data within the table as a unique identifier.
5 0
3 years ago
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