Let's rewrite the system of equations: y = three over four times x squared minus 3 y = (3/4) x ^ 2 - 3 y = negative three over four times x squared plus 3 y = (-3/4) x ^ 2 + 3 The system of equations is: y = (3/4) x ^ 2 - 3 y = (-3/4) x ^ 2 + 3 The solutions are: (-2, 0) (2, 0) Answer: See attached image