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Triss [41]
3 years ago
7

I need help with a faceing math worksheet

Mathematics
1 answer:
kupik [55]3 years ago
4 0

2^2=32

(3x7-7)=14

32-14=18

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I need help please don't know this
SashulF [63]

Answer:

9 is the right answer

Step-by-step explanation:

I. If c = - 4 and d = 10

      then \frac{1}{4}(-4^{3} + 10^{2}  )

           = \frac{1}{4}(-64 + 100)

          = \frac{1}{4}(36)

          = 9

Hope that help :D

6 0
3 years ago
The owners of the pet sitting business have set aside $48 to purchase chewy toys for dogs, 2,
Contact [7]

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more angles and variables.

Let x represent the number of dogs and y represent the number of cats collars. Hence:

At Marco's market:

2x + 6y = 48 (1)

At Sonia's superstore:

4x + 4y = 48  (2)

Graphing both equations, the solution is at (6,6)

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

Find out more on Equation at: brainly.com/question/13763238

7 0
1 year ago
A flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 14 feet mor
miv72 [106K]

Answer:

onii chan zani moto veno . sain culoco naiso

Step-by-step explanation:zani nqqa quasetni onii san 4

6 0
3 years ago
Please help! will give brainliest!
sergeinik [125]
Answer:

Arc PL = 62
Arc QPS = 258

Explanation:

17. 5x-19 = 2x+11

18.

16x - 28 = 180.
7 0
2 years ago
A cookie factory monitored the number of broken cookies per pack yesterday.
trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given  

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20  

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } } \leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

2.290 < S < 2.965

8 0
2 years ago
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