P(centre engine and left fail) = 0.004 x 0.007 = 0.000028
P(centre engine and right fail) = 0.004 x 0.007 = 0.000028
P(all three engines fail) = 0.004 x 0.007 x 0.007 = 0.000000196
P(plane will crash) = 0.000028 x 2 + 0.000000196 = 0.000056196
Answer:
A. Normal distribution
Step-by-step explanation:
I just did it on usatestprep
Military discount, I guess...
I think the answer might be B identify the initial amount