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Sphinxa [80]
3 years ago
13

The proper sequence to use in solving 3x - 2 = 60 is:

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0
If you follow the steps of PEMDAS it should be Multiply by 3,subtract 2.
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A geometric sequence can be used to describe the population of rabbits on a
vlabodo [156]

Answer:

step 1

Find the average growth per year of the populations of rabbits farm A

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=40

average=[40-5]/2---------> 17.5

step 2

Find the average growth per year of the populations of rabbits farm B

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=30

average=[30-5]/2---------> 12.5

step 3

Compare the average growth per year of the populations of rabbits on both farms

farm A=17.5

farm B=12.5

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.

therefore

the answer is the option C)

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.

Step-by-step explanation:

6 0
2 years ago
Simplify the expression <br><br> 64 7/12
VladimirAG [237]
775/12 , is your answer.
8 0
3 years ago
Read 2 more answers
A hose fills a hot tub at a rate of 3.74 gallons per minute. How many hours will it take to fill a 289- gallon hot tub?
Inessa05 [86]
I think it would take about 1 hour and 17 minutes
6 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
Anybody know what the answer is
koban [17]
5. million 6. Ten thousand
6 0
3 years ago
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