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Katena32 [7]
3 years ago
7

HELP DUE IN 15 MIN x =

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

x=7

Step-by-step explanation:

write -2+16x+9x+7=180

then add all like terms (-2+7=5) and (16x+9x=25x)

5+25x=180

-5. -5

25x=175

/25. /25

x=7

zubka84 [21]3 years ago
5 0

Answer:

180=-2+16x+9x+7

180=25x+5

-5. -5

175=25x

175/25=25x/25

7= x

Step-by-step explanation:

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Fancy goldfish x cost $3 each and common goldfish y cost $1 each.Graph the function y=20-3x to determine how many of each type o
aniked [119]

The pairs of goldfish Tasha can buy for $20 are (0,20), (1,17), (2,14),

(3,11),(4,8),(5,5),and (6,2)

Step-by-step explanation:

To find the how many type of goldfish that Tasha can buy for $20 is the set of positive ordered pairs.

Let x denote the number of fancy goldfish.

Let y denote the number of common goldfish.

To find how much goldfish can Tasha buy for $20 is to substitute the value for x in the equation y=20-3x

Now, substituting x=0 in y=20-3x, we get,

y=20

The ordered pair is (0,20)

Similarly, substituting x=1,

y=20-3(1)\\y=20-3\\y=17

For x=2,

y=20-6\\y=14

For x=3,

y=20-9\\y=11

For x=4,

y=20-12\\y=8

For x=5,

y=20-15\\y=15

For x=6,

y=20-18\\y=2

Thus, the pairs of goldfish Tasha can buy for $20 are (0,20), (1,17), (2,14),(3,11),(4,8),(5,5),and (6,2)

4 0
3 years ago
HURRYYY PLEASEEEE
masha68 [24]
The answer is 7/25.
4 0
3 years ago
I need help finding the value of x please.
mariarad [96]
In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side.
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Question: Write an algebraic expression that represents how many total cars there are on the Toyota car lot if there are r rows
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The algebraic expression is 37 x r = x
8 0
3 years ago
Blacktop Refining extracts minerals from ore mined at two different sites in Montana. Each ton of ore type 1 contains 20% copper
Kisachek [45]

Answer:

a) Minimize Cost=90x_1+120x_2

subject to

0.2x_1+0.3x_2\geq8

0.2x_1+0.25x_2\geq6

0.15x_1+0.1x_2\geq5

x_1\geq0\\x_2\geq0

b) Attached

c) The optimum value that minimizes cost is x1=28 and x2=8.

Step-by-step explanation:

The objective function is the cost of extraction and needs to be minimized.

The cost of extraction is the sum of the cost of extraction of ore type 1 and the cost of extraction of ore type 2:

Cost=90x_1+120x_2

Being x1 the tons of ore type 1 extracted and x2 the tons of ore type 2.

The constraints are the amount of minerals that need to be in the final mix

Copper:

0.2x_1+0.3x_2\geq8

Zinc

0.2x_1+0.25x_2\geq6

Magnesium

0.15x_1+0.1x_2\geq5

Of course, x1 and x2 has to be positive numbers.

x_1\geq0\\x_2\geq0

The feasible region can be seen in the attached graph.

The orange line is the magnesium constraint. The red line is the copper constraint. The green line is the zinc constraint.

The optimal solution is found in one of the intersection points between two constraints that belong to the limits of the feasible region.

In this case, the cost can be calculated for the 3 points that satisfies the conditions.

The optimum value that minimizes cost is x1=28 and x2=8.

4 0
3 years ago
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