The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
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Answer:
a - 30.2
b - 271.8
Step-by-step explanation:
60/4=15
60/3=20
9+6.45+2.4+8.15+4.2=30.2
30.2x9=271.8
I hope this helps you
2 (B+4)=3
B+4=3/2
B=3/2-4
B=-5/2
You need to substitute the number 6 into the function. The output would be 72, because when l(6) = 12(6), you would get l(6) = 72.
Answer:
t = 137-w
Step-by-step explanation:
