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MrRa [10]
4 years ago
5

Using factor theorem, factorise x⁴-x³-7x²+x+6

Mathematics
2 answers:
andrew11 [14]4 years ago
8 0

Answer:

Add and subtract the second term to the expression and factor by grouping .

(x-1)(x+1)(x-3)(x+2)

garik1379 [7]4 years ago
5 0

Answer:

(x-1)(x-3)(x+1)(x+2)

Step-by-step explanation:

x⁴-x³-7x²+x+6=

x⁴-x³-x²+x -6x²+6=

x³(x-1)-x(x-1)-6(x²-1)=

x³(x-1)-x(x-1)-6(x-1)(x+1)=

(x-1)(x³-x-6x-6)=

(x-1)(x³-3x²+3x²-9x+2x-6)=

(x-1)(x-3)(x²+3x+2)=

(x-1)(x-3)(x²+x+2x+2)=

(x-1)(x-3)(x+1)(x+2)

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f(-1) is substituted for f(x) so you must look at -1 on the x axis.

Once you've located -1 on the x-axis, locate what it equals to answer the question.

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3 years ago
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Ira Lisetskai [31]

Answer:

8

Step-by-step explanation:

as side of square are equal

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3 years ago
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If a/4 = b/7, what is the value of a-b/b?
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what is the solution to the equation fraction 1 over 3(n − fraction 1 over 3) = fraction 1 over 6n? n = 3 n = 2 n = fraction 5 o
Nat2105 [25]
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3 years ago
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Step-by-step explanation:

1. You have the following inequality given in the problem:

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2. You must solve for x.

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