Question

At a store, apples cost $0.80 $0.80 each and oranges cost $0.95 $0.95 each. Harry buys some apples and oranges and spends $9.55 $9.55 . He buys a total of 11 11 pieces of fruit.

Answer 1

Answer:

Harry buys 6 apples and 5 oranges at the store.

Step-by-step explanation:

Given:

Cost of each apples = $0.8

Cost of each oranges = $0.95

Total money spend =$9.55

Number of fruits bought= 11

We need to find the number of apples bought and number of oranges were bought.

Solution:

Let the number of apples bought be 'a'.

Let the number of oranges were bought be 'o'.

Number of fruits bought= 11

So we can say that;

Number of fruits bought is equal to sum number of apples bought and number of oranges were bought.

framing in equation form we get;

$a+o=11$ ⇒ equation 1

Now we can say that;

Total money spend is equal to number of apples bought multiplied by Cost of each apples plus number of oranges were bought multiplied by Cost of each oranges.

framing in equation form we get;

$0.8a+0.95o=9.55$ ⇒ equation 2

Now Multiplying equation 1 by 0.8 we get;

$0.8(a+o)=0.8\times11$

$0.8a+0.8o=8.8$ ⇒ equation 3

Subtracting equation 3 from equation 2 we get;

$0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75$

Dividing both side by 0.15 we get;

$\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5$

Substituting the value of o in equation 1 we get;

$a+o=11\\\\a+5=11\\\\a=11-5=6$

Hence Harry buys 6 apples and 5 oranges at the store.