All categories

3 years ago

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect.

Mathematics

2 answers:

MrRa [10]3 years ago

7 0

Answer:

p = 2 and q = 14

Step-by-step explanation:

f(g(x)) = 3(px + 4) + p

f(g(x)) = 3px + 12 + p

6x + q = 3px + 12 + p

The trick here is to equate the coefficients.

6 = 3p and q = 12 + p

p = 2 and q = 14

Volgvan3 years ago

3 0

Answer:

if fg(x)=6x+q

then f(gx) =6x+q

3(px+4)+p =6x+q

3px+12+p = 6x+q

3px+p = 6x+q-12

make p the subject

p( 3x+1) = 6x+q-12

p= (6x + q -12 )/ 3x +1

You might be interested in

Can someone help me please ASAP

zmey [24]

Answer:

solution,

Let <DEF= x°

<CDE= 2x°

<BAF= 90°

The sum of interior angle of hexagon= 720°

<A + <B + <C + <D + <E +<F = 720°

$90 + 145 + 115 + 2x + x + 160 = 720 \\ 510 + 3x = 720 \\3x + 510 = 720 \\ 3x + 510 - 510 = 720 - 510 \\ 3x = 210 \\ \frac{3x}{x} = \frac{210}{3} \\ x = 70 \: degree$

Again,

$< \: cde = 2x \\ \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 70 \\ \: \: \: \: \: \: \: \: \: \: \: \: = 140 \: degree$

Hope this helps...

Good luck on your assignment..

4 0

3 years ago

Simplify the equation

Arturiano [62]

Answer:

$\dfrac{16x^3-37x^2-16x+37}{x^2+2}$

Step-by-step explanation:

There aren't any factors that cancel (except 3x). The best you can do is multiply it out.

$\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}$

7 0

4 years ago

Is the following shape a rectangle? how do you know?

Usimov [2.4K]

Slope of AB = 1/3 and slope of BC = -3 so these 2 lines are perpendicular
The same is true for all the other adjjacent pairs of lines.
Oppoitse lines are also paralllel ( slope of AB = 1/3 and slope of DC = 1/3) and other pair are both of slope -3.

So Its C

8 0

3 years ago

Solve the function.<br> h(x)= 6x - 10<br> ————-<br> X + 3 <br><br><br> Help please

Rus_ich [418]

Answer:

X+3=0

X=-3

H(x)=6*-3 - 10

H(x) =-18 - 10

H(x) =-28

8 0

3 years ago

Given that Segment BE is 5 units, find the indicated measures for each

zalisa [80]

Answer:

The indicated measure of the length of AE = 5 units

Step-by-step explanation:

To determine:

What is the indicated measure of length?

Information Fetching and Solution Steps:

From this single diagram, it seems the indicated measure of length which we have to determine is the length of AE.

Given that Segment BE is 5 units. i.e. BE = 5 units

As the square has two equal diagonals AC and DB which meet at point E.

So, point E being the common mid-point of both diagonals.

As both of the diagonals of square are equal in length.

And the length of BE is 5 units, which is half the length of BD. It means the diagonal BD has a length of 10 units.

And since both diagonals AC and DB are equal in length, it means the length of AC must be 10 units.

Since, AC has the length of 10 units, it means the length of AE must be half of the length of AC. Thus, the indicated measure of the length of AE is 5 units.

Therefore, the indicated measure of the length of AE = 5 units

Keywords: square, diagonals, length, line segment

Learn more about square diagonals from brainly.com/question/628263

#learnwithBrainly

6 0

3 years ago

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect. ​

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect.