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3 years ago

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect.

Mathematics

2 answers:

MrRa [10]3 years ago

7 0

Answer:

p = 2 and q = 14

Step-by-step explanation:

f(g(x)) = 3(px + 4) + p

f(g(x)) = 3px + 12 + p

6x + q = 3px + 12 + p

The trick here is to equate the coefficients.

6 = 3p and q = 12 + p

p = 2 and q = 14

Volgvan3 years ago

3 0

Answer:

if fg(x)=6x+q

then f(gx) =6x+q

3(px+4)+p =6x+q

3px+12+p = 6x+q

3px+p = 6x+q-12

make p the subject

p( 3x+1) = 6x+q-12

p= (6x + q -12 )/ 3x +1

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3 years ago

5. If the covariance between the variables x and y is 18 and the variance

klasskru [66]

Answer:

The coefficient of correlation=0.5

Step-by-step explanation:

We are given that

Covariance between the variable x and y=18

Variance of x=16

Variance of y=81

We have to find the coefficient of correlation

We know that

Coefficient of correlation

$r=\frac{covariance(x,y)}{\sqrt{variance(x)}\times \sqrt{variance(y)}}$

Using the formula

$r=\frac{18}{\sqrt{16}\times \sqrt{81}}$

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Hence, the coefficient of correlation=0.5

5 0

3 years ago

erica [24]

Answer:

20% decrease

Step-by-step explanation:

First, let's find the net decrease: Peter started at 80kg and his weight is now 64kg, which is a 16kg decrease. Next, we need to find what percentage of 80kg 16kg represents. First, let's find what part of 80 is 16:

16/80 = 1/5

To convert this to a percent, we need to find an equivalent fraction to 1/5 with a denominator of 100. To do this, we can multiply the numerator and denominator of 1/5 by 20, giving us 20/100, or 20%.

4 0

3 years ago

The functions from part A are f(x) = 2.5e-0.04x and g(x) = 1.2 + 0.2x. Enter the expression that results from f(x) − g(x). Give

Goryan [66]

Answer:

f(x)-g(x)

2.5e-0.04x-1.2+0.2

7 0

3 years ago

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect. ​

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect.