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Arturiano [62]
3 years ago
13

I have been asked this question and I substituted the value of x in f with g(x), and rearranged the equality but is incorrect. ​

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

Answer:

p = 2 and q = 14

Step-by-step explanation:

f(g(x)) = 3(px + 4) + p

f(g(x)) = 3px + 12 + p

6x + q = 3px + 12 + p

The trick here is to equate the coefficients.

6 = 3p and q = 12 + p

p = 2 and q = 14

Volgvan3 years ago
3 0

Answer:

if fg(x)=6x+q

then f(gx) =6x+q

3(px+4)+p =6x+q

3px+12+p = 6x+q

3px+p = 6x+q-12

make p the subject

p( 3x+1) = 6x+q-12

p= (6x + q -12 )/ 3x +1

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x = 60° (Alternate angles)

Step-by-step explanation:

a) x = 60°

b) Reason: Alternate angles

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Kendrick adds 1/2cup of chicken stock to a pot. Then he takes 1/2 cup of stock out of the pot. What is the overall increase or d
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2 years ago
What is the average rate of change between hour 15 and hour 30
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Rearrange y= 2(x-a)/x to make x the subject
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Answer:

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3 0
2 years ago
Read 2 more answers
Several years​ ago, 38​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
Colt1911 [192]

Answer:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values are:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The estimated proportion of people satisfied with the quality of education the students receive is given by:

\hat p =\frac{499}{1165}= 0.428

The confidence interval for the proportion if interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing the info given we got:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0
3 years ago
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