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Ad libitum [116K]
3 years ago
11

Exit

Mathematics
1 answer:
wlad13 [49]3 years ago
7 0
C, 3,5 cm, 3,5 cm, 3.5 cm hope it helps

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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7Bx%5E%7B2%7D-8x%2B8%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\in
12345 [234]

Answer:

{ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx}  \: =  \:  - 1}}

Step-by-step explanation:

{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\  \\ =  { \tt{[ \frac{ {x}^{3} }{3}  - 4 {x}^{2}  + 8x ] {}^{2} _{1}}}

Substitute x with the limits:

= { \tt{( \frac{ {2}^{3} }{3}  - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3}  - 4( {1)}^{2}  + 8(1)) }} \\  = { \tt{( \frac{8}{3}  -  \frac{11}{3} )}} \\  \\  = { \tt{ - 1}}

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3 years ago
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Step-by-step explanation:

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