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Ad libitum [116K]
3 years ago
11

Exit

Mathematics
1 answer:
wlad13 [49]3 years ago
7 0
C, 3,5 cm, 3,5 cm, 3.5 cm hope it helps

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What is 384,304 estimated
Kisachek [45]
It depends what your teacher wants it rounded to. It could be 300,000 if its rounded to the hundred thousands. If it is to the nearest hundred, it would be 384,300.

7 0
3 years ago
Plz help with all of it !
DiKsa [7]
1)

a) 3/9= 0.333333333333 but you can just say 0.3
b) 4/3= 1.333333333333 but you also can say 1.33 or just 1.3

2)

a) 21/8, 21 over 8 if you solve you would get 2.625
b) 7(divide sign)4, which is also 7/4, if you solve you would get 1.75
c) 4/9 , 4 over 9 if you solve you would get 0.444444444 which is 0.4
d) 9/7, 9 over 7, if you solve it would be 1.285 which is 1.3


6 0
3 years ago
I need help with this please
MissTica
Divide to find the answer
5 0
3 years ago
What is the fourth term of a number pattern that begins with 250 and subtracts 13? A. 211 B. 224 C. 198 D. 302
Alina [70]

Create the equation:

250-13x

Plug in 4 for the equation and solve:

250-13(4)

250-52

198

The answer is C. 198

3 0
3 years ago
Read 2 more answers
What are the degrees of freedom for Student's t distribution when the sample size is 19? d.F. = Use the Student's t distribution
liq [111]

Answer:

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0
3 years ago
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