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riadik2000 [5.3K]

2 years ago

t\limits^2_1 {x^{2}-8x+8 } \, dx" alt="\int\limits^2_1 {x^{2}-8x+8 } \, dx" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

12345 [234]2 years ago

4 0

Answer:

${ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx} \: = \: - 1}}$

Step-by-step explanation:

${ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\ \\ = { \tt{[ \frac{ {x}^{3} }{3} - 4 {x}^{2} + 8x ] {}^{2} _{1}}}$

Substitute x with the limits:

$= { \tt{( \frac{ {2}^{3} }{3} - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3} - 4( {1)}^{2} + 8(1)) }} \\ = { \tt{( \frac{8}{3} - \frac{11}{3} )}} \\ \\ = { \tt{ - 1}}$

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The given question is incomplete. The complete question is:

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