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riadik2000 [5.3K]
3 years ago
12

t\limits^2_1 {x^{2}-8x+8 } \, dx" alt="\int\limits^2_1 {x^{2}-8x+8 } \, dx" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

{ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx}  \: =  \:  - 1}}

Step-by-step explanation:

{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\  \\ =  { \tt{[ \frac{ {x}^{3} }{3}  - 4 {x}^{2}  + 8x ] {}^{2} _{1}}}

Substitute x with the limits:

= { \tt{( \frac{ {2}^{3} }{3}  - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3}  - 4( {1)}^{2}  + 8(1)) }} \\  = { \tt{( \frac{8}{3}  -  \frac{11}{3} )}} \\  \\  = { \tt{ - 1}}

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