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riadik2000 [5.3K]
3 years ago
12

t\limits^2_1 {x^{2}-8x+8 } \, dx" alt="\int\limits^2_1 {x^{2}-8x+8 } \, dx" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

{ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx}  \: =  \:  - 1}}

Step-by-step explanation:

{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\  \\ =  { \tt{[ \frac{ {x}^{3} }{3}  - 4 {x}^{2}  + 8x ] {}^{2} _{1}}}

Substitute x with the limits:

= { \tt{( \frac{ {2}^{3} }{3}  - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3}  - 4( {1)}^{2}  + 8(1)) }} \\  = { \tt{( \frac{8}{3}  -  \frac{11}{3} )}} \\  \\  = { \tt{ - 1}}

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Answer: Complementary angles. x = 60

How I got it.

x - 30 + x = 90

then solve for x

Hope this helps!

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HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?
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Answer:

<h3>           B(10, 6)</h3>

Step-by-step explanation:

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then:

x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6

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2 years ago
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5x+12= -13 (find the x)
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8 0
2 years ago
Read 2 more answers
X - 32.2 = 18.5 how do you solved this
Salsk061 [2.6K]

x-32.2= 18.5

Add 32.2 to both sides

x-32.2+32.2 = 18.5 + 32.2

x = 50.7

I hope that's help !


Check your answer

replace x by its number

50.7-32.2= 18.5

18.5 = 18.5

so the answer is good .


Please let me know if you have question(s) !


3 0
3 years ago
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