3 years ago

What is the set builder form for [6,7,8,9, ....]

Mathematics

1 answer:

Shalnov [3]3 years ago

5 0

Step-by-step explanation:

the set builder form for [6,7,8,9, ....] is given as:

$\{x : x = n, \: \: n \in \: N, \: \: n \geqslant 6 \}$

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Step-by-step explanation:

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2 years ago

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Bingel [31]

Solution:

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$\frac{1}{5 - \sqrt{2} }$

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Therefore, multiplying and dividing by 5 + √2, we have

$= \frac{1}{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} } \\ = \frac{5 + \sqrt{2} }{(5 - \sqrt{2})(5 + \sqrt{2} ) } \\ = \frac{5 + \sqrt{2} }{ {(5)}^{2} - ( \sqrt{2})^{2} } \\ = \frac{5 + \sqrt{2} }{25 - 2} \\ = \frac{5 + \sqrt{2} }{23}$

Answer:

$\frac{5 + \sqrt{2} }{23}$

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3 years ago

What is the set builder form for [6,7,8,9, ....]​

What is the set builder form for [6,7,8,9, ....]