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Kitty [74]
3 years ago
8

Express 1+√2/√2 in the form p+q√2​

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

\frac{1+\sqrt{2}}{\sqrt{2}} = \frac{1}{\sqrt{2}} + \frac{\sqrt{2}}{\sqrt{2}} = 1 + \frac{1}{\sqrt{2}}

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PLEASE HELP
Thepotemich [5.8K]

Answer:

i think E.942 cm³ is answer

Volume = πr²h

so

3.14×5×5×12

= 942 cm²

5 0
2 years ago
Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (
Vladimir79 [104]

Answer:

Factors: (x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

Step-by-step explanation:

We are given a polynomial:

f(x)=x^4-x^3-2x-4

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

8 0
3 years ago
Help??I have 4 questions and im confused on all of them
KengaRu [80]
So you you are trying to find the area of sphere so you would use this formula
A=4•3.14•r^2

And you already know that the radius is 6 so you would go ahead and plug in the numbers
A=4•3.14•4^2

4^2 is 16 so your final equation would be
A=4•3.14•16

And your answer is

=452.39
4 0
3 years ago
Lisa had 1750 stamps. Mark had 480 fewer stamps than Lisa. Lisa gave some stamps to Mark. Now Mark has three times as many stamp
FrozenT [24]
L: 1750, M:1750-480=1270
Lisa gave some stamps to Mark so Lisa now has 1750-x and Mark has 1270+x. Mark also has 3 times as many as Lisa now: (1750-x)*3=1270+x
5250-3*x=1270+x
4*x=3980, x=3980/4, x=995
So Lisa gave 995 stamps to Mark.
At first Mark had 1270 stamps. Lisa now has 1750-995=755 stamps.
7 0
3 years ago
Read 2 more answers
(04.02 MC)
Elena L [17]

Answer:

0.1384

Step-by-step explanation:

Using binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Given n = 25, r = 4, p = 0.10, and q = 0.90:

P = ₂₅C₄ (0.10)⁴ (0.90)²⁵⁻⁴

P = 12650 (0.10)⁴ (0.90)²¹

P = 0.1384

6 0
3 years ago
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