Answer:
Approximately 206 grams.
Explanation:
How many moles of sulfuric acid
are there in this solution?
.
The unit for concentration "
" is equivalent to mole per liter. In other words,
. For this solution, the concentration of
is
.
.
What's the mass of that
of
?
Start by finding the molar mass
of
.
Relative atomic mass data from a modern periodic table:
- H: 1.008;
- S: 32.06;
- O: 15.999.
.
.
.
In other words, the chemist shall need approximately 206 grams of
to make this solution. As a side note, keep in mind that the 206 grams of
also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.
A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.
Important of Grignard Reagent :
Grignard reactions are main due to their capacity to form carbon-carbon bonds. Grignard reagents are powerful bases and will react with protic compounds which makes them exceptionally valuable implement for organic synthesis.
Grignard reagents react fastly with acidic hydrogen atoms in molecules such as alcohols and water. When a Grignard reagent reacts with water, a proton return back halogen, and the product is an alkane. The Grignard reagent therefore provides a trace for transforming a haloalkane to an alkane in two steps.
When reacted with water,
RMgX + H2O -------> R-H + MgOH X
R ---- Alkyl Group
X --- Halogen
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The thing you MUST do FIRST is look for any H's, O's, or F's in the equation
1)any element just by itself not in a compound, their oxidation number is 0
ex: H2's oxidation number is 0
ex: Ag: oxidation number is 0 if its just something like Ag + BLA = LALA
2) the oxidation number of H is always +1, unless its just by itself (see #1)
3) the oxidation number of O is always -2, unless its just by itself (see #1)
4) the oxidation number of F is always -1, unless its just by itself (see#1)
ok so after you have written those oxidation numbers in rules 1-4 over each H, F, or O atom in the compound, you can look at the elements that we havent talked about yet
for example::::
N2O4
the oxidation number of O is -2.
since there are 4 O's, the charge is -8. now remember that N2O4 has to be neutral so the N2 must have a charge of +8
+8 divided by 2 = +4
N has an oxidation number of +4.
more rules:
5) the sum of oxidation numbers in a compound add up to 0 (when multiplied by the subscripts!!!) (see above example)
6) the sum of oxidation numbers in a polyatomic ion is the charge (for example, PO4 has a charge of (-3) so
oxidation # of O = -2. (there are 4 O's = -8 charge on that side ) P must have an oxidation number of 5. (-8+5= -3), and -3 is the total charge of the polyatomic ion
Answer:
44,55 can be produced.
Explanation:
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent


Now, we find the limiting reagent from the quantities of product that can be formed from each reagent


1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag =
= 44,55g
Ag≈ 44,6g