Saturated oils are oils where every carbon is sp3 hybridized and attached to two other carbons and two hydrogen. An unsaturated oil features a pi bond and a sigma bond between one or more carbons. This sigma bond interacts with Br2 by way of an addition reaction, the double bond is broken and two bromine are added to the carbon chain. The resulting structure is colorless so in a way the oil absorbs the colored Br2 into a colorless molecule. So, the more Saturated an oil is, the more Br2 it can accept and that's why Br2 can be used to detect the presence of satiated oils. While adding Br2, the solution will stay colorless as long as there are double bonds to accept it.
Hope this makes sense, if you've talked about reaction mechanisms this should be pretty straightforward.
The answer would 5.66 x 10 power of 24
The question is incomplete, the complete question is;
AlBr3 can be used as a catalyst in the Friedel-Crafts alkylation reaction. The correct name for the compound represented by the formula AlBr3 is —
aluminum bromide
monoaluminum tribromide
aluminide bromine
aluminum tribromide
Answer:
aluminum bromide
Explanation:
Having known that AlBr3 is an ionic compound and aluminium is the central atom here, we now have to ask ourselves if Aluminium exists in other stable oxidation states.
We must take cognizance of the fact that the oxidation number of the central atom in a compound becomes part of the name of that compound when other stable oxidation states for atoms of the same elements exists.
Since the +3 state is the only stable oxidation state for aluminium, the name of the compound is simply aluminium bromide.
It is an alkaline earth metal.
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