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marusya05 [52]
3 years ago
5

Is the molecule BF3 is a resonance structure?

Chemistry
1 answer:
Pavel [41]3 years ago
4 0
No, because the valance of boron is 3 and its satisfied by 3
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What type(s) of intermolecular forces are expected between PF2Cl3 molecules?a. dispersion.b. dipole-dipole.c. ion-ion.d. hydroge
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Answer:

dispersion.

Explanation:

The molecule, PF2Cl3 is trigonal bipyramidal. The dipoles in the molecule cancel out since there is a symmetric charge distribution around the molecule hence the resultant dipole moment of the molecule is zero.

If the molecule is nonpolar, then the dominant intermolecular forces present are the weak dispersion forces, hence the answer above.

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3 years ago
The following chemical equation is not balanced: Fe2O3 + H2SO4 Fe2(SO4)3 + H2O When this chemical equation is correctly balanced
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c. 3
3 0
3 years ago
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What formula can be used to calculate [H30+]
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[H3O+] is just the same with [H+]. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14
Read more on Brainly.com - brainly.com/question/1365379#readmore
4 0
4 years ago
Which of the following types of energy equals the total energy of motion and position
AURORKA [14]
A. mechanical energy because it can be either potential or kinetic energy and it wouldn't be d because moving energy is the same as kinetic energy.
8 0
4 years ago
A polymer sample combines five different molecular-weight fractions, each of equal weight. The molecular weights of these fracti
kakasveta [241]

Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20  *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100  *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi  = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000  =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

7 0
3 years ago
Read 2 more answers
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