Describe a covalent bond?

1 answer:

Natasha2012 [34]3 years ago

7 0

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

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The concentration of potassium is higher in red blood cells than in the surrounding blood plasma. This higher concentration is m

lana [24]

Answer:

active transport

Explanation:

Active transport -

It refers to the movement of the molecules from a region of lower concentration towards a region of higher concentration via a membrane , is referred to as active transport.

The process of active transport need to have some cellular energy .

Hence,

The concentration of potassium is maintained in the red blood cells via the process of active transport.

3 0

3 years ago

Which of the following are nonelectrolytes? Hc2h302 (acetic acid) CH30H (method alcohol) h2So4 and c12h22011 (sucrose or table s

hoa [83]

Answer:

C₁₂H₂₂O₁₁ and CH₃OH

Explanation:

Sucrose and methyl alcohol are nonelectrolytes. They do not ionize or conduct a current in aqueous solution.

HC₂H₃O₂ is a weak electrolyte. It produces only a few ions and is a poor conductor of electricity in aqueous solution.

HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O₂⁻

H₂SO₄ is a strong electrolyte. Its first ionization is complete, so it is a good conductor of electricity in aqueous solution.

H₂SO₄ + H₂O ⟶ H₃O⁺ + HSO₄⁻

8 0

3 years ago

An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 5.00g of this compound produced 7.33g of

Olegator [25]

A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:

Organic Compound + Oxygen = CO2 + H2O

To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.

7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C

Therefore, 0.167 mol of C was originally in the sample.

8 0

3 years ago

Read 2 more answers

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s).

pychu [463]

Answer:

26.110 grams of O2 produced.

Explanation:

Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.

To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.

39.098 + 35.45 + (15.999 * 3) = 122.548.

66.7g / 122.548 atomic mass = 0.544 moles.