Answer:
The circulation of the field f(x) over curve C is Zero
Step-by-step explanation:
The function 
and curve C is ellipse of equation
Theory: Stokes Theorem is given by:
Where, Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Also, f(x) = (F1,F2,F3)
Using Stokes Theorem,
Surface is given by g(x) = 
Therefore, tex]\hat{N} = grad(g(x))[/tex]
Now,
Curl f(x) =
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5Cx%5E%7B2%7D%264x%26z%5E%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = (0,0,4)
Putting all values in Stokes Theorem,
I=0
Thus, The circulation of the field f(x) over curve C is Zero
Answer:
.D. 4√2 cm
Step-by-step explanation:
With reference angle 45°
base (b) = 4 cm
hypotenuse (h) = AC
Now
Cos 45° = b /h
1/√2 = 4 / AC
AC = 4√2 cm
Answer:
Step-by-step explanation:
<u>Given line:</u>
<u />
<u>The y-intercept is the point when x = 0:</u>
The point is (0, - 5)
<u />
<u>The x-intercept is the point when y = 0:</u>
- - x + 0 = - 5
- - x = - 5
- x = 5
The point is (5, 0)
Step-by-step explanation:
A is correct option there are no real roots
because discriminant is less than zero
What are you trying to find ?
