Given the triangle below, what is m triangleA, rounded to the nearest tenth?
2 answers:
Answer:
The correct answer is option A 17.8°
Step-by-step explanation:
From the figure attached with this answer,
We can see a perpendicular from B to side AC
<u>To find BD</u>
In triangle BDC, its angles are 30°, 60° and 90°
Therefore the sides are in the ratio 1 :√3 : 2
Here BC = 11
BD : DC : BC = 1 :√3 : 2 = 11√3/2 : 11/2 : 11
Therefore BD = 11/2
<u>To find the value of m<A</u>
We have
Sin ∅ = Opposite side /Hypotenuse
AB = 18 and BD = 11/2
Sin A = BD/AB =(11/2)/18 = 11/36 = 0.3055
m<A = Sin⁻¹(0.3055) = 17.79 ≈ 17.8°
Therefore the correct answer is option A 17.8°
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Plugging in values, we get that (1,-4) works.
Answer:
x < -2
Step-by-step explanation:
1. Original Inequality: 10 – 2(2x + 2) > 14
2. 10-4x-4>14
<em>Distribute the -2 to 2x and 2. </em>
3. Simplify the left side: 6-4x>14
<em>Do 10-4 </em>
4. Subtract: -4x>8
<em>Subtract 6 from both sides to get x by itself</em>
5. Divide: x< -
<em>You want to divide by -4 that way you can find what x is. When you divide OR multiply by a negative number in an inequality you are going to need to switch the way the sign is facing.</em>
6. Simplify: x< -2
7. Check:
10-2(2(-3) +2) > 14
10-2(-6 + 2)
10-2(-4)
10+8
18 > 14