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Feliz [49]
3 years ago
12

PLSSSSSS HELPPPPPPP FAST WILL GIVE BRAINLIEST ITS IREADY!!!!!!!!!!! PLSSSSS HELPPPPPPPPPPPPPP

Mathematics
2 answers:
Scilla [17]3 years ago
8 0
8/2 = 4 it is the ratio
soldi70 [24.7K]3 years ago
7 0

Answer:

8:1

Step-by-step explanation:

Okay so the ratio from cocoa to sugar from the chart is 8:2. To simplify this you could multiply both sides by 2 which would get you 4:1 or 4. Now the question asks what is the ratio Leah will use when this is doubled. In order to do this you can multiply 4 by 2 which gets you 8. Or 8:1. Hope you understand :)

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PLEASE PLEASE PLEASE HELP Determine an equation for the pictured graph. Write your answer in factored form and assume the leadin
notsponge [240]

Answer:

f(x)=-x(x+2)(x-1)^2

Step-by-step explanation:

From inspection, the curve has 3 turning/stationary points, which suggests it is quartic function.  In factored form:  ax(x + b)(x + c)(x + d)

From inspection, there are 3 roots at: x = -2,  x = 0,  x = 1

Therefore x, (x + 2) and (x - 1) will be factors.  

Whenever a turning/stationary point touches the x-axis, we conclude that a root is repeated at that point.  Therefore, from inspection, root x = 1 is a repeated root.  So  x, (x + 2) and (x - 1)² are factors.

The quartic curve is a "n" shape, which means the leading coefficient is negative.  We are told the leading coefficient is + or - 1. Therefore, it will be -1.

Therefore, an equation for the function in factored form is:

f(x)=-x(x+2)(x-1)^2

8 0
3 years ago
What is the following product
Ira Lisetskai [31]

Answer: The answer to your question will be -

5^√16x^4

7 0
4 years ago
Read 2 more answers
How can the equation of a parabola be derived when given the focus and the directrix?
Annette [7]
The distance between any point (x0,y0) on the parabola and the focus (m,n) is the same as the distance between (x0,y0) and the directrix line ax+by+c. The distance between (x0,y0) and focus (a,b) is \sqrt((x-m)^2+(y-n)^2). The distance between (x0,y0) and ax+by+c is |ax0+by0+c|/\sqrt(m^2+n^2).  Equalize these two expressions.
4 0
4 years ago
Reflecting the graph of y = sinx across the y-axis is the same as reflecting it across
sp2606 [1]

Answer:

The statement is true.

Step-by-step explanation:

Given : Reflecting the graph of y = sin x across the y-axis is the same as reflecting it across the x-axis.

To find : Is this statement true or false?

Solution:

Rules of reflection :

Along across y-axis if we have a point

So, y=sinx

The reflection across y-axis→ .......[1]

Along across x-axis if we have a point

so, y=sinx

The reflection across x-axis →  .....[2]

Hence, [1] and [2] both of them are equal

Therefore, the statement is true.

8 0
3 years ago
Read 2 more answers
PLEASE HURRY I need to submit RIGHT NOWWWWWW AJHHHH
ira [324]

Answer:

y=1/2x -5

because it starts at -5 on the y axis and goes up 2 squares and over 1 square

6 0
3 years ago
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