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Snezhnost [94]
4 years ago
11

Which number makes this sentence true?

Mathematics
2 answers:
Marta_Voda [28]4 years ago
7 0
It's letter a ......................
Semmy [17]4 years ago
3 0
The answer is a) x=30
You might be interested in
If you shift the linear parent function , f(x)=x, down 7 units
kolbaska11 [484]

Answer:

f(x) = x - 7

This is because the b value determines the y intercept, and if you move the function down 7, you are technically subtracting 7 from the current b value which was 0.

4 0
4 years ago
If f(x)=3x-2 and g(x)=x^2+1, find f(g(-1)) and g(f(3))
julsineya [31]

Answer:

f(g(-1))=4

g(f(3))=50

Step-by-step explanation:

We know the definition of both functions: f(x)=3x-2, and g(x)=x^2+1

A) In order to evaluate what f(g(-1)) is, let's first investigate what g(-1) is using the definition for this function:

g(x)=x^2+1\\g(-1)=(-1)^2+1\\g(-1)=1+1\\g(-1)=2

Now let's find what f(2) is using f(x) definition: f(x)=3x-2\\f(2)=3(2)-2\\f(2)=6-2\\f(2)=4

B) In order to evaluate what g(f(3)) is, let's first investigate what f(3) is using the definition for this function:

f(x)=3x-2\\f(3)=3(3)-2\\f(3)=9-2\\f(3)=7

Now let's find what g(7) is using the definition for this function:

g(x)=x^2+1\\g(7)=(7)^2+1\\g(7)=49+1\\g(7)=50

4 0
3 years ago
NEED HELP ASAP PLEASE
vovikov84 [41]

Answer:

The fourth one I believe

Step-by-step explanation:

3 0
3 years ago
3x + 4y= 16 solve for y
Pepsi [2]
   3x + 4y = 16
<u>- 3x             -3x</u> 
          4y = -3x + 16     (divide each side by 4)
         \frac{4y}{4} =  \frac{-3x+16}{4}
          y = -3/4x + 16/4
  
The answer is  y =-  \frac{3}{4}x +4
5 0
4 years ago
If t a n squared θ = 3 /8 , what is the value of  s e c θ
TEA [102]

We can use 3 facts:

\tan{\theta}=\frac{y}{x}

\sec{\theta}=\frac{r}{x}

x^2+y^2=r^2

So, to find our x and our y we can do:

\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}So, now that we know our x and our y we can find our r.

(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}

You'll notice, though, that there were two solutions for \tan{\theta}, which means we have a positive and a negative for our x. So:

\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}

7 0
3 years ago
Read 2 more answers
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