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4 years ago

Which number makes this sentence true?

Mathematics

2 answers:

Marta_Voda [28]4 years ago

7 0

It's letter a ......................

Semmy [17]4 years ago

3 0

The answer is a) x=30

You might be interested in

X+100+31=180. what does X=? *<br> Nour answer

mr_godi [17]

Answer:

Step-by-step explanation:

x + 100 + 31 = 180

x + 100 + 31 - 100 - 31 = 180 -100 -31

x = 49

5 0

4 years ago

Which graph represents the solution set of and ?

Anit [1.1K]

Answer:

<h2>GRAPH III</h2>

Step-by-step explanation:

Look at the picture.

We have

y = x² - 4 → move the graph of x² 4 units down (the vertex is (0, -4))

x + y + 2 = 0 <em>subtracy x and 2 from both sides</em>

y = -x - 2 → move the graph of -x 2 units down (the y-intercept os -2)

Only graph III and IV meets these conditions.

The solution is the points of intersection of the graphs.

Therefore your answer is GRAPH III

<em />

8 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

4 years ago

Solve for y.

storchak [24]

Subtract 1.05 from both sides. Then, you will end up with y= 6.21. So, C.

5 0

4 years ago

93 divided by 3 using repeated subtraction

Naily [24]

93/3=31 Answer is 31

8 0

3 years ago

Read 2 more answers