Y-3.6=x^2
y=x^2+3.6
x=1, y=4.6
x=3,y=9.6
x=5,y=28.6
x=6,y=39.6
x=9,y=84.6
Combine like terms in Qx + 12 = 13x + P:
x(Q-13) = P-12
P-12
Then x = ----------
Q-13
Note that Q may not = 13. But none of the answer choices present Q = 13.
Let's go thru the answer choices one by one.
P-12
x = ----------
Q-13
-24
Check out A: Q=12 and P= -12: x = -------- = 24 This is OK (ONE sol'n)
-1
-25
Check out B: Q = -13 and P = -13: x = ----------- = 25/26 OK
-26
13-12
Check out C: Q = -13 and P = 13: x = ------------ = -1/26 OK
-13-13
12-12
Check out D: Q = 12 and P = 12: x= ---------- = 0 OK
12-13
It appears that in all four cases, the equation has ONE solution.
Answer:
which one equals 12? option C
Step-by-step explanation:
1) 8 turning points means 8 vertices, which implies minimum degree 9 (when the polynomial is x^2 the degree is 2 and it has one turning point).
2) 5 turning points means minimum degree 6, 3 zeros means minimum degree 3, the multiplication implies minimum degree 6+3 = 9
3) 5 times crossing the x - axis is 5 zeros, then the minimum degree is 5.
4) f(x)=x^14 + x^6 + x^9 + x^3,maximum number of turning points 14 -1 = 3 (remember one less than the grade is the maximum posible number of turning points, but it could be less, for example f(x) = x^2 has one turning point).
