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mixas84 [53]
4 years ago
12

In two or more complete sentences, describe the transformation(s) that take place on the parent function, f(x) = log(x), to achi

eve the graph of g(x) = log(-2x-4) + 1.
Mathematics
2 answers:
zheka24 [161]4 years ago
8 0

The parent function  that is f(x) = log(x)  is transformed  firstly, to log(x+2)

since, we can see after that we can directly convert it to log(2x+4)

and after one reflection it will become log(-2x-4)

NOTE: Reflection is the mirror image so it will directly comes to the opposite quadrant

after one reflection graph will  be shifted to  one unit up vertically.

user100 [1]4 years ago
7 0

Answer:

1) Shift 2 unit left

2) Flip the graph about y-axis

3) Stretch horizontally by factor 2

4) Shift vertically up by 1 units

Step-by-step explanation:

Given:

Parent function: f(x) = \log(x)

Transformation function: g(x) = \log(-2x-4) + 1

Re-write the transformed function by taking -2 common,

g(x) = \log(-2(x+2)) + 1

Step 1 -

f(x) = \log(x)

Shift 2 unit left i.e, f(x)→f(x+b) shifting left by b unit

f(x)=\log(x+2)

Step 2 -

Flip the graph about y-axis i.e, f(x)→ -f(x)

f(x)=\log[-(x+2)]

Step 3 -

Stretch horizontally by factor 2 i.e, f(x)→f(bx) stretch horizontally by b unit

f(x)=\log[-2(x+2)]

Step 4 -

Shift vertically up by 1 units i.e, f(x)→f(x)+b shifting vertically by b unit

f(x)=\log[-2(x+2)]+1

Thus, In 4 steps transformation is done.

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For more details,

Let

cos(B) = (3/5), then

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2 years ago
The Sahara Desert has an area of approximately 9,400,400 km2. While estimates of its average depth vary, they center around 150
dolphi86 [110]

Answer:

1.128048 \times 10^{25} grains of sand are in the Sahara Desert

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The Sahara Desert has an area of approximately 9,400,400 sq.km.

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To Find :Approximately how many grains of sand are in the Sahara Desert?

Solution:

Area of Sahara desert = 9,400,400 sq.km.

1 km^2 = 1000000 m^2

So, 9,400,400 km^2 = 1000000 \times 9400400 m^2

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1 m ^3 = 1000000 cm^3

So, 1.41006\times 10^{15} m^3 = 1.41006\times 10^{15} \times 1000000cm^3

1.41006\times 10^{15} m^3 =1.41006 \times 10^{21}cm^3

1 cubic cm holds grains of sand = 8000

1.41006 \times 10^{21}cm^3 holds grains of sand = 1.41006 \times 10^{21} \times 8000

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