Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,
p = 1 - 0.81 = 0.91
n = 9 students
x = number of success = 3
The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,
P(x = 2) = 0.297
I believe the answer is C
