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2 years ago

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anonymous anonymous 2 years ago Math Help Please!! :) Crystal earns $5.25 per hour mowing lawns. Write a rule to describe how th

e amount of money m earned is a function of the number of hours h spent mowing lawns. How much does Crystal earn if she works 2 hours and 15 minutes? A) m(h) = 2h + 15; $25.50 B) m(h) = h/5.25; $0.43 C) m(h) = 5.25h; $11.29 D) m(h) = 5.25h; $11.81 Mathematics

1 answer:

aivan3 [116]2 years ago

8 0

It should be B or D. B because in 2 hours you make $10.50 and then add 15 minutes and you get B. It could also be D because that's doing $5.25 an hour which is true it's just deleting the extra 45 minutes so it can be either B or D.

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What is the surface area of a sphere with radius 4?

mario62 [17]

Answer: 64 units

Step-by-step explanation:

Remember, the formula to find surface area given radius is $4\pi r^2$ . Let's add in the given information:

4pi4^2 =

4pi16

64pi!

Hope this helps, please consider making me Brainliest.

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1 year ago

A. Do some research and find a city that has experienced population growth.

horrorfan [7]

A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation $N_{t} =N _{0}e^{rt}$
where:
$N(t)$ is the population after $t$ years
$N_{0}$ is the initial population
$t$ is the time in years
$r$ is the growth rate in decimal form
$e$ is the Euler's constant
We now for our investigation that $N(t)=238300$ , $N_{0} =192157$ , and $t=10$ ; lets replace those values in our equation to find $r$ :
$238300=192157e^{10r}$
$e^{10r} = \frac{238300}{192157}$
$ln(e^{10r} )=ln( \frac{238300}{192157} )$
$r= \frac{ln( \frac{238300}{192157}) }{10}$
$r=0.022$
Now lets multiply $r$ by 100% to obtain our growth rate as a percentage:
$(0.022)(100)$ =2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that $N(t)=713777$ , $N_{0} =951307$ , and $t=10$ . Just like before, lets replace those values into our equation to find $r$ :
$713777=951307e^{10r}$
$e^{10r} = \frac{713777}{951307}$
$ln(e^{10r} )=ln( \frac{713777}{951307} )$
$r= \frac{ln( \frac{713777}{951307}) }{10}$
$r=-0.029$
$(-0.029)(100)$ = -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: $N(t)=192157e^{0.022t}$ .
Final equation from point B: $N(t)=951307e^{-0.029t}$
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations $N(t)=192157e^{0.022t}$ and $N(t)=951307e^{-0.029t}$ and solve for t:
$192157e^{0.022t} =951307e^{-0.029t}$
$\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1$
$e^{0.051t} = \frac{951307}{192157}$
$ln(e^{0.051t})=ln( \frac{951307}{192157})$
$t= \frac{ln( \frac{951307}{192157}) }{0.051}$
$t=31.36$
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be $2(951307)=1902614$ . Now we can rewrite our equation as: $N(t)=1902614e^{-0.029t}$ . The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
$192157e^{0.022t} =1902614e^{-0.029t}$
$\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1$
$e^{0.051t} = \frac{1902614}{192157}$
$ln(e^{0.051t} )=ln( \frac{1902614}{192157} )$
$t= \frac{ln( \frac{1902614}{192157}) }{0.051}$
$t=44.95$
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit.

8 0

3 years ago

The world population is projected to be 6.7 billion in 2040. At that time, there are expected to be approximately 2 billion mor

Charra [1.4K]

$\bf \begin{cases}
s=\textit{Asia's population}\\
a=\textit{Africa's population}\\
r=\textit{rest of the world}\\
----------\\
\boxed{s}=a+2\\
\boxed{r}=\frac{s}{2}+0.2
\end{cases}\implies 
\begin{array}{llll}
s+a+r=6.7\\\\
\boxed{a+2}+a+\boxed{\cfrac{s}{2}+0.2}=6.7\\\\
a+2+a+\cfrac{\boxed{a+2}}{2}+0.2=6.7
\end{array}$

solve for "a", to see what Africa's population will then be

5 0

3 years ago

A fair die is tossed 5 times. Let <img src="https://tex.z-dn.net/?f=%5Cdfrac%7Bm%7D%7Bn%7D" id="TexFormula1" title="\dfrac{m}{n}

Ray Of Light [21]

Answer:

m = 1

Step-by-step explanation:

We can suppose that the number we are looking for is for example 5.

(we can do so because the probability is the same for each number - it'sna fair dice)

For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).

For the second toss the probability we have 5 is again 1/6.

For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)

Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.

We can see that m = 1.

4 0

3 years ago

Need answer ASAP <br> *MARKING BRAINLIEST

Luba_88 [7]

Answer:

252 in²

Step-by-step explanation:

Recall area of regular polygon is A= (1/2)*(perimeter)*(apothem)

Area = (1/2)*(63)*(7)

= 252 in²

7 0

3 years ago

Read 2 more answers