<em><u>Question:</u></em>
? Liter equivalent to 0.000 000 000 013 cubic kilometers
How do we do it?´
<em><u>Answer:</u></em>
13 liter is equivalent to 0.000 000 000 013 cubic kilometers
<em><u>Solution:</u></em>
Given that,
? Liter equivalent to 0.000 000 000 013 cubic kilometers
So we have to convert cubic kilometer to liter
<em><u>Use the following conversion factor</u></em>

Therefore,

Thus, 13 liter is equivalent to 0.000 000 000 013 cubic kilometers
Answer:
D'(-6,-4)
Step-by-step explanation:
When making this non rigid transformation about a point, keep in mind that a dilation by a certain scale factor can be represented by:
Answer:
no, there is an infatuate amount of solutions
Step-by-step explanation:
1.2(2x-5)=2/5(2x-15)+1.6x
2.4x -6 = .8x -6 +1.6
2.4 -6 = 2.4-6
0=0 ( infatuate)
Answer:
C. A graph is drawn. The horizontal axis and vertical axis values are 0 to 70 in increments of 10. The horizontal axis label is Number of Pies, and the vertical axis label is Pounds of Cherries. Points are plotted on the ordered pairs 30, 20 and 45, 30 and 60, 40.
Step-by-step explanation:
If we take two of the original points from the data and put them in to two point form we get the following equation.
(6,4) and (12,8)
(y-4) = [(8-4)/(12-6)](x-6)
y = 2/3x
You have to start a the origin since we can only have enough ingredients to make pies and we can't start with partial pies. So move to y intercept up by 2.
Put the x values in for answer C and you'll return the y values.
Step-by-step explanation:
(a) ∫₋ₒₒ°° f(x) dx
We can split this into three integrals:
= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx
Since the function is even (symmetrical about the y-axis), we can further simplify this as:
= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx
The first integral is finite, so it converges.
For the second integral, we can use comparison test.
g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.
We can show that g(x) converges:
∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).
Therefore, the smaller function f(x) also converges.
(b) The width of the intervals is:
Δx = (3 − -3) / 6 = 1
Evaluating the function at the beginning and end of each interval:
f(-3) = e^(-9/2)
f(-2) = e^(-2)
f(-1) = e^(-1/2)
f(0) = 1
f(1) = e^(-1/2)
f(2) = e^(-2)
f(3) = e^(-9/2)
Apply Simpson's rule:
S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]
S ≈ 2.5103