Question

X^2 - 10x + 13 = 0 Solve quadratic equation In simplest form

Answer 1

Answer:

$5 \pm 2\sqrt{3}$

Step-by-step explanation:

A quadratic equation in the form

$ax^2+bx+c=0$

Can be solved by using the formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In this problem, the equation is

$x^2-10x+13=0$

So, we have

a = 1

b = -10

c = +13

Using the equation above, we find:

$x=\frac{-(-10)\pm \sqrt{(-10)^2-4(1)(13)}}{2(1)}=\frac{10 \pm \sqrt{48}}{2}=\frac{10 \pm 4\sqrt{3}}{2}= 5 \pm 2\sqrt{3}$