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tamaranim1 [39]
4 years ago
9

X^2 - 10x + 13 = 0 Solve quadratic equation In simplest form

Mathematics
1 answer:
Salsk061 [2.6K]4 years ago
8 0

Answer:

5 \pm 2\sqrt{3}

Step-by-step explanation:

A quadratic equation in the form

ax^2+bx+c=0

Can be solved by using the formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

In this problem, the equation is

x^2-10x+13=0

So, we have

a = 1

b = -10

c = +13

Using the equation above, we find:

x=\frac{-(-10)\pm \sqrt{(-10)^2-4(1)(13)}}{2(1)}=\frac{10 \pm \sqrt{48}}{2}=\frac{10 \pm 4\sqrt{3}}{2}= 5 \pm 2\sqrt{3}

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The diagonals of a trapezoid are equal.<br><br> A) always<br> B) sometimes<br> C) never
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3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
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Answer:

(1204 ; 1288) ;

(1162 ; 1330) ;

(1120 ; 1372)

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mean ± 1(standard deviation)

(1246 - 1(42)) ; (1246 + 1(42))

1204 ; 1288

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95% is within two standard deviation of the mean ;

Therefore 95% equals ;

mean ± 2(standard deviation)

(1246 - 2(42)) ; (1246 + 2(42)

(1246 - 84) ; (1246 + 84)

(1162 ; 1330)

c. a range of years centered about the mean in Which almost all the data (tree-ring dates) Will be found between_____ and A.D.

About 99.7% which is within 3 standard deviations of the mean

99.7% is within 3 standard deviations of the mean ;

Therefore ;

mean ± 3(standard deviation)

(1246 - 3(42)) ; (1246 + 3(42))

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3 years ago
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I did not understand
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