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Mkey [24]
3 years ago
8

Simplify 5 to the negative third power

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0
I don't know if I'm right but I think its -243
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Andy is designing a dice tray in the shape of a rectangular prism to use during a role-playing game. The tray needs to be three
Dmitry_Shevchenko [17]

Answer:

3x^2 + 15x - 252 = 0

Step-by-step explanation:

The volume of the prism is 252 cubic centimeters.

The volume of a rectangular prism is gotten by the formula:

V = l * w * h

where l = length

w = width

h = height

The height of the prism is 3 cm.

Let x be the width of the prism.

The length of the prism is 5 cm longer than the width.That is:

l = 5 + x

The volume of the prism is therefore:

V = (5 + x) * x * 3

=> 252 = (5x + x^2) * 3\\\\252 = 15x + 3x^2\\\\=> 3x^2 + 15x - 252 = 0

This is the equation that models the volume of the tray in terms of x.

6 0
3 years ago
Alan bowls one game, which consists of 10 frames. The number of pins he knocked down in each frame is 5, 6, 7, 5, 7, 9, 2, 4, 8,
Igoryamba
A measure of the center
4 0
4 years ago
According to a survey done at your school, about 42% of all the female students participate in 2 sport seasons. You randomly ask
IRISSAK [1]

Answer: 0.353

Step-by-step explanation:

We know that 42% of all the female students participate in 2 sports this season. (58% is the percent that did not)

This means that if we select a random student, there is a 0.42 probability that the student did participate in 2 sports this season.

Other thing that i will use is that, if we have a group of N objects, and we want to create a group of K objects out of the N, the number of combinations is:

c = \frac{N!}{(N - K)!*K!}

Now, out of 5, we want to find the proability that, at least 3 of them, did participate in at least 2 sports this season.

The probability that all 5 of them participated, is equal to the product of the individual probabilities. (so N = 5, and K = 5)

P = (0.42^5)*1 = 0.013

Now, if only 4 of them did participate (N = 5, k = 4), the probability is equal to:

P = (0.42^4)*(0.58)*5!/4! = (0.42^4)*(0.58)*5 = 0.09

The probability for only 3 is: (N = 5 and K = 3)

P = (0.42^3)*(0.58^2)*5!/(3!*2!) = (0.42^3)*(0.58^2)*(5*4/2) = 0.25

Then the total probability is:

P = 0.013 + 0.09 + 0.25 = 0.353

7 0
3 years ago
Ming drew the model below to represent the equation 24 + 12 = blank x (8 + 4). A model with 3 rows of 8 and 3 rows of 4. What is
Mila [183]

Given:

The equation is:

24+12=\_\_\times (8+4)

A model with 3 rows of 8 and 3 rows of 4.

To find:

The missing value in Ming's equation.

Solution:

We have,

24+12=\_\_\times (8+4)           ...(i)

A model with 3 rows of 8 and 3 rows of 4. Using this information, we get

24+12=3\times 8+3\times 4

Taking out the common factor 3, we get

24+12=3\times (8+4)               ...(ii)

On comparing (i) and (ii), we get the missing value is 3.

Therefore, the missing value in Ming's equation is 3.

3 0
3 years ago
PLS HELP I'LL GIVE THE BRAINLEST
vazorg [7]

Answer:

first box    y=4/7x+2

second box y=-1/7x+2

thrid box y=x+2

4th box y+1/7x+2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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