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Alexxx [7]
2 years ago
8

Help pls ill mark brainliest

Mathematics
1 answer:
Naily [24]2 years ago
3 0

Answer:

A. 2,310 sq ft

Step-by-step explanation:

<u>R</u><u>e</u><u>c</u><u>t</u><u>e</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>b</u><u>e</u><u>l</u><u>o</u><u>w</u><u>:</u>

  • A = l × b
  • A = 74 × 15
  • A = 1,110ft

<u>Rectangle Above</u><u>:</u>

  • A = l × b
  • A = 50 × 24
  • A = 1,200ft

<u>A</u><u>r</u><u>e</u><u>a</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>l</u><u>a</u><u>y</u><u>g</u><u>r</u><u>o</u><u>u</u><u>n</u><u>d</u><u>:</u>

  • 1,110ft + 1,200ft
  • 1,310 sq ft (A)
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Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
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Answer:

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the times of a population, and for this case we know the distribution for X is given by:

X \sim N(129.71,2.5)  

Where \mu=129.71 and \sigma=2.5

Since we want the middle 75% values then on tha tails we need 1-0.75 =0.25 or 25% of the data and since the distribution is symmetric we need 12.5 % of the values on each tail.

For this part we want to find a value a and b, such that we satisfy this condition:

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P(X   (b)

We can use the z score formula in order to find the value a and b given by:

z=\frac{x-\mu}{\sigma}  

As we can see on the figure attached the z value that satisfy the condition (b) with 0.125 of the area on the left and 0.875 of the area on the right it's z=-1.15. On this case P(Z<-1.15)=0.125 and P(z>-1.15)=0.875

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.15

And if we solve for a we got

a=129.71 -1.15*2.5=126.835

So the value of height that separates the bottom 12.5% of data from the top 87.5% is 126.835.

As we can see on the figure attached the z value that satisfy the condition (b) with 0.875 of the area on the left and 0.125 of the area on the right it's z=1.15. On this case P(Z<1.15)=0.875 and P(Z>1.15)=0.125  

If we use condition (b) from previous we have this:

P(X>b)=P(\frac{X-\mu}{\sigma}>\frac{b-\mu}{\sigma})=0.125  

P(Z>\frac{b-\mu}{\sigma})=0.125

But we know which value of z satisfy the previous equation so then we can do this:

Z=1.15>\frac{b-129.71}{2.5}

And if we solve for a we got

b=129.71 +1.15*2.5=132.585

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

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