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Ede4ka [16]
3 years ago
8

Plzz help i dont understand

Mathematics
1 answer:
tangare [24]3 years ago
7 0
There's no picture up
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24 students in a class took an algebra a test. If 18 students passed the test what percent passed?
stiks02 [169]

Answer:

75% of students passed

Step-by-step explanation: divide 18 by 24 to find the precentage

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For triangle S F C, angle S is 90 degrees, angle F is 49 degrees, and angle C is 41 degrees. For triangle Z P K, angle Z is 41 d
leva [86]

Answer:

I'm pretty sure he or she are right^^idk

Step-by-step explanation:

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(English to algebra) twice K results in three times the sum of k plus one
babymother [125]

i believe its 2k= 3(k+1)

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A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
3 years ago
Simplify (2+7) divided by (7-2 times 2)
Step2247 [10]
1.111.... so just right 1.2
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